1
/ 10
中等
第 1 题
已完成 0 题
练习设置
题目内容
数学
初中
选择题
请选择一道题目开始练习
我的笔记
答案解析
请选择一道题目查看解析
练习完成!
恭喜您完成了本次练习
0
总题数
0
正确
0
错误
答题卡
[{"id":891,"subject":"数学","grade":"初一","stage":"初中","type":"填空题","content":"在一次班级环保活动中,某学生收集了若干个废旧电池。他将这些电池分成两类:可回收的和不可回收的。已知可回收电池的数量比不可回收的多6个,两类电池总数为24个。设不可回收电池的数量为x,则可列出方程:x + (x + 6) = 24。解这个方程,不可回收电池有___个。","answer":"9","explanation":"根据题意,设不可回收电池数量为x,则可回收电池数量为x + 6。两类电池总数为24,因此方程为x + (x + 6) = 24。化简得2x + 6 = 24,两边减去6得2x = 18,再除以2得x = 9。所以不可回收电池有9个。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-30 02:08:37","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":1098,"subject":"数学","grade":"七年级","stage":"初中","type":"填空题","content":"在一次班级环保活动中,某学生收集了可回收垃圾共12.5千克,其中废纸占8.3千克,塑料瓶占2.7千克,其余为金属。若金属的重量用代数式表示为 12.5 - 8.3 - 2.7,则金属的重量是___千克。","answer":"1.5","explanation":"根据题意,金属的重量等于总重量减去废纸和塑料瓶的重量,即 12.5 - 8.3 - 2.7。先计算 12.5 - 8.3 = 4.2,再计算 4.2 - 2.7 = 1.5。因此,金属的重量是1.5千克。本题考查有理数的加减运算在实际问题中的应用,属于简单难度。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-06 08:57:01","updated_at":"2026-01-06 08:57:01","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":633,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某班级组织植树活动,计划在一条笔直的小路一侧每隔5米种一棵树,起点和终点都种。如果一共种了13棵树,那么这条小路的长度是多少米?","answer":"A","explanation":"这是一道结合实际情境的一元一次方程应用题,考查学生对植树问题中间隔数与棵数关系的理解。已知每隔5米种一棵树,起点和终点都种,共种13棵树。由于两端都种树,间隔数 = 棵数 - 1 = 13 - 1 = 12(个)。每个间隔5米,因此总长度为 12 × 5 = 60(米)。所以正确答案是A。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 21:57:45","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"60米","is_correct":1},{"id":"B","content":"65米","is_correct":0},{"id":"C","content":"55米","is_correct":0},{"id":"D","content":"70米","is_correct":0}]},{"id":2184,"subject":"数学","grade":"七年级","stage":"初中","type":"选择题","content":"某学生在数轴上标出三个点A、B、C,分别表示有理数a、b、c。已知a < b < c,且|a| = |c|,b是a与c的中点。若c = 5,则a + b + c的值是多少?","answer":"B","explanation":"由题意知c = 5,且|a| = |c|,所以|a| = 5,即a = 5或a = -5。又因a < b < c且c = 5,若a = 5,则a = c,与a < c矛盾,故a = -5。b是a与c的中点,即b = (a + c) ÷ 2 = (-5 + 5) ÷ 2 = 0。因此a + b + c = -5 + 0 + 5 = 0。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"中等","points":1,"is_active":1,"created_at":"2026-01-09 14:21:04","updated_at":"2026-01-09 14:21:04","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"-5","is_correct":0},{"id":"B","content":"0","is_correct":1},{"id":"C","content":"5","is_correct":0},{"id":"D","content":"10","is_correct":0}]},{"id":2130,"subject":"数学","grade":"七年级","stage":"初中","type":"选择题","content":"某学生在解方程时,将方程 2(x + 3) = 10 的两边同时除以2,得到 x + 3 = 5,然后解得 x = 2。该学生的解法是否正确?如果正确,原方程的解是什么?","answer":"B","explanation":"该学生将方程 2(x + 3) = 10 两边同时除以2,得到 x + 3 = 5,这是合法的等式变形(等式两边同除以一个非零数,等式仍成立)。接着移项得 x = 5 - 3 = 2,解得正确。因此解法正确,且原方程的解确实是 x = 2。选项B正确。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-09 12:56:39","updated_at":"2026-01-09 12:56:39","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"解法错误,因为不能两边同时除以2","is_correct":0},{"id":"B","content":"解法正确,原方程的解是 x = 2","is_correct":1},{"id":"C","content":"解法正确,但原方程的解是 x = 4","is_correct":0},{"id":"D","content":"解法错误,因为应该先展开括号再求解","is_correct":0}]},{"id":212,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"一个长方形的长是8厘米,宽是5厘米,它的周长是____厘米。","answer":"26","explanation":"长方形的周长计算公式是:周长 = 2 × (长 + 宽)。将长8厘米和宽5厘米代入公式,得到:2 × (8 + 5) = 2 × 13 = 26。因此,这个长方形的周长是26厘米。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 14:39:57","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":2292,"subject":"数学","grade":"八年级","stage":"初中","type":"选择题","content":"某学生测量了一块直角三角形纸片的两条直角边,分别为5 cm和12 cm。若要用一根细线沿着纸片的边缘完整绕一圈,所需细线的最短长度是多少?","answer":"A","explanation":"题目要求计算直角三角形纸片的周长,即三条边之和。已知两条直角边分别为5 cm和12 cm,首先利用勾股定理求斜边:斜边 = √(5² + 12²) = √(25 + 144) = √169 = 13 cm。因此,周长为 5 + 12 + 13 = 30 cm。所需细线的最短长度即为周长,故正确答案为A。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-10 10:42:42","updated_at":"2026-01-10 10:42:42","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"30 cm","is_correct":1},{"id":"B","content":"25 cm","is_correct":0},{"id":"C","content":"17 cm","is_correct":0},{"id":"D","content":"13 cm","is_correct":0}]},{"id":1985,"subject":"数学","grade":"九年级","stage":"初中","type":"选择题","content":"某学生在纸上画了一个边长为12 cm的正方形ABCD,并以顶点A为旋转中心,将正方形绕点A逆时针旋转30°。若点B在旋转过程中所经过的路径长度为多少?(π取3.14,结果保留两位小数)","answer":"A","explanation":"本题考查旋转与圆的综合应用,重点在于理解点绕定点旋转时路径为圆弧。正方形边长为12 cm,点B到旋转中心A的距离为AB = 12 cm,即旋转半径为12 cm。当正方形绕点A逆时针旋转30°时,点B的轨迹是以A为圆心、半径为12 cm、圆心角为30°的圆弧。圆弧长度公式为:L = (θ\/360°) × 2πr,其中θ = 30°,r = 12 cm。代入得:L = (30\/360) × 2 × 3.14 × 12 = (1\/12) × 75.36 ≈ 6.28 cm。因此,点B经过的路径长度约为6.28 cm。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-07 15:03:19","updated_at":"2026-01-07 15:03:19","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"6.28 cm","is_correct":1},{"id":"B","content":"12.56 cm","is_correct":0},{"id":"C","content":"18.84 cm","is_correct":0},{"id":"D","content":"25.12 cm","is_correct":0}]},{"id":250,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"一个长方形的长比宽多5厘米,若其周长为38厘米,则这个长方形的宽是___厘米。","answer":"7","explanation":"设长方形的宽为x厘米,则长为(x + 5)厘米。根据长方形周长公式:周长 = 2 × (长 + 宽),代入已知条件得:2 × (x + x + 5) = 38。化简得:2 × (2x + 5) = 38,即4x + 10 = 38。解得4x = 28,x = 7。因此,长方形的宽是7厘米。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"中等","points":1,"is_active":1,"created_at":"2025-12-29 14:54:08","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":1969,"subject":"数学","grade":"七年级","stage":"初中","type":"选择题","content":"某学生在研究某次校园义卖活动中不同商品的销售情况时,记录了五种商品的销售额(单位:元):125.6, 98.4, 142.3, 110.8, 135.7。为了分析这组数据的集中趋势,该学生计算了这组数据的中位数和平均数,并发现两者存在一定差异。若将这组数据按从小到大的顺序排列后,位于中间位置的数据与所有数据之和除以数据个数的结果之差最接近以下哪个数值?","answer":"B","explanation":"本题考查数据的收集、整理与描述中中位数与平均数的计算及比较。首先将五种商品的销售额从小到大排序:98.4, 110.8, 125.6, 135.7, 142.3。由于数据个数为5(奇数),中位数是第3个数,即125.6。接着计算平均数:(125.6 + 98.4 + 142.3 + 110.8 + 135.7) ÷ 5 = 612.8 ÷ 5 = 122.56。然后计算中位数与平均数之差:125.6 - 122.56 = 3.04。该值最接近选项B(2.8)。因此,正确答案为B。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"中等","points":1,"is_active":1,"created_at":"2026-01-07 14:48:51","updated_at":"2026-01-07 14:48:51","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"1.2","is_correct":0},{"id":"B","content":"2.8","is_correct":1},{"id":"C","content":"3.6","is_correct":0},{"id":"D","content":"4.4","is_correct":0}]}]