1
/ 10
中等
第 1 题
已完成 0 题
练习设置
题目内容
数学
初中
选择题
请选择一道题目开始练习
我的笔记
答案解析
请选择一道题目查看解析
练习完成!
恭喜您完成了本次练习
0
总题数
0
正确
0
错误
答题卡
[{"id":2456,"subject":"数学","grade":"八年级","stage":"初中","type":"填空题","content":"在△ABC中,∠C=90°,AC=5,BC=12。若点D在斜边AB上,且CD⊥AB,则CD的长度为______。","answer":"60\/13","explanation":"先由勾股定理得AB=13,再利用等面积法:S△ABC=½×5×12=½×13×CD,解得CD=60\/13。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"中等","points":1,"is_active":1,"created_at":"2026-01-10 14:00:56","updated_at":"2026-01-10 14:00:56","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":966,"subject":"数学","grade":"初一","stage":"初中","type":"填空题","content":"某学生测量了学校花坛中5株向日葵的高度(单位:厘米),分别为:82,75,90,78,_85_。如果这5株向日葵的平均高度是82厘米,那么被遮盖的那个数据应该是多少?","answer":"85","explanation":"已知5株向日葵的平均高度是82厘米,因此总高度为 5 × 82 = 410 厘米。已知的四个高度分别是82、75、90、78,它们的和为 82 + 75 + 90 + 78 = 325 厘米。所以被遮盖的数据为 410 - 325 = 85 厘米。本题考查数据的收集与整理中的平均数计算,属于简单难度,符合七年级‘数据的收集、整理与描述’知识点。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-30 04:03:03","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":156,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"已知一个三角形的两边长分别为5cm和8cm,第三边的长度可能是以下哪一个?","answer":"B","explanation":"根据三角形三边关系定理:任意两边之和大于第三边,任意两边之差小于第三边。已知两边为5cm和8cm,则第三边x应满足:8 - 5 < x < 8 + 5,即3 < x < 13。选项中只有5cm在这个范围内,因此正确答案是B。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-24 11:57:36","updated_at":"2025-12-24 11:57:36","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"3cm","is_correct":0},{"id":"B","content":"5cm","is_correct":1},{"id":"C","content":"13cm","is_correct":0},{"id":"D","content":"15cm","is_correct":0}]},{"id":355,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"在一次班级环保活动中,某学生收集了废旧纸张和塑料瓶共30件,其中废旧纸张比塑料瓶多6件。设塑料瓶的数量为x件,则根据题意可以列出的一元一次方程是:","answer":"A","explanation":"题目中已知废旧纸张和塑料瓶共30件,且废旧纸张比塑料瓶多6件。设塑料瓶为x件,则废旧纸张为(x + 6)件。根据总数关系,可列出方程:x + (x + 6) = 30。选项A正确表达了这一数量关系。其他选项中,B表示纸张比塑料瓶少6件,与题意相反;C和D忽略了其中一种物品的数量,不符合题意。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 15:43:26","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"x + (x + 6) = 30","is_correct":1},{"id":"B","content":"x + (x - 6) = 30","is_correct":0},{"id":"C","content":"x + 6 = 30","is_correct":0},{"id":"D","content":"x - 6 = 30","is_correct":0}]},{"id":313,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某班级为了了解学生最喜欢的课外活动,随机抽取了50名学生进行调查,并将数据整理成如下统计表。已知喜欢阅读的学生人数是喜欢绘画的2倍,且喜欢运动的人数比喜欢绘画的多10人。如果喜欢音乐的学生有8人,那么喜欢绘画的学生有多少人?","answer":"B","explanation":"设喜欢绘画的学生人数为x人。根据题意,喜欢阅读的人数是2x人,喜欢运动的人数是x + 10人,喜欢音乐的有8人。总人数为50人,因此可以列出方程:x(绘画) + 2x(阅读) + (x + 10)(运动) + 8(音乐) = 50。合并同类项得:4x + 18 = 50。解这个一元一次方程:4x = 32,x = 8。所以喜欢绘画的学生有8人。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 15:36:07","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"6人","is_correct":0},{"id":"B","content":"8人","is_correct":1},{"id":"C","content":"10人","is_correct":0},{"id":"D","content":"12人","is_correct":0}]},{"id":1835,"subject":"数学","grade":"八年级","stage":"初中","type":"选择题","content":"如图,在平面直角坐标系中,点 A(0, 4)、B(3, 0)、C(0, 0) 构成直角三角形 ABC,∠C 为直角。将 △ABC 沿直线 y = x 翻折得到 △A'B'C',则点 B' 的坐标是( )。","answer":"A","explanation":"本题综合考查轴对称与坐标变换、勾股定理及一次函数图像的理解。已知直线 y = x 是翻折对称轴,翻折即关于直线 y = x 作轴对称变换。在平面直角坐标系中,一个点 (a, b) 关于直线 y = x 的对称点为 (b, a)。因此,点 B(3, 0) 关于直线 y = x 的对称点 B' 的坐标为 (0, 3)。验证:点 A(0, 4) 对称后为 A'(4, 0),点 C(0, 0) 对称后仍为 (0, 0),符合翻折性质。故正确答案为 A。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"中等","points":1,"is_active":1,"created_at":"2026-01-06 16:49:35","updated_at":"2026-01-06 16:49:35","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"(0, 3)","is_correct":1},{"id":"B","content":"(3, 0)","is_correct":0},{"id":"C","content":"(4, 0)","is_correct":0},{"id":"D","content":"(0, 4)","is_correct":0}]},{"id":2333,"subject":"数学","grade":"八年级","stage":"初中","type":"选择题","content":"某公园内有一块三角形花坛ABC,工作人员在边AB外侧作等边三角形ABD,在边AC外侧作等边三角形ACE。连接BE和CD,交于点F。若∠BFC = 120°,则△ABC的形状最可能是以下哪种?","answer":"A","explanation":"本题综合考查全等三角形与轴对称思想的应用。由于△ABD和△ACE均为等边三角形,可得AB = AD,AC = AE,且∠BAD = ∠CAE = 60°。因此∠DAC = ∠BAE(同加∠BAC),从而可证△DAC ≌ △BAE(SAS),进而推出∠ABE = ∠ADC。进一步分析可知,BE与CD的交角∠BFC与∠BAC互补。题目给出∠BFC = 120°,故∠BAC = 60°。同理可推∠ABC = ∠ACB = 60°,因此△ABC为等边三角形。此结论也符合几何构造中的旋转对称性——将△ABE绕点A逆时针旋转60°可与△ADC重合,进一步验证了结论。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"中等","points":1,"is_active":1,"created_at":"2026-01-10 10:55:39","updated_at":"2026-01-10 10:55:39","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"等边三角形","is_correct":1},{"id":"B","content":"等腰直角三角形","is_correct":0},{"id":"C","content":"含30°角的直角三角形","is_correct":0},{"id":"D","content":"一般锐角三角形","is_correct":0}]},{"id":939,"subject":"数学","grade":"初一","stage":"初中","type":"填空题","content":"在一次环保知识竞赛中,某班级学生共收集了120条有效答题记录。经统计,其中答对一题得3分,答错或不答扣1分。若该班级总得分为280分,则他们答对了____道题。","answer":"100","explanation":"设答对的题数为x,则答错或不答的题数为(120 - x)。根据得分规则,总得分为3x - 1×(120 - x) = 280。化简方程得:3x - 120 + x = 280,即4x = 400,解得x = 100。因此,他们答对了100道题。本题考查一元一次方程的实际应用,属于简单难度。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-30 03:12:36","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":616,"subject":"数学","grade":"初一","stage":"小学","type":"选择题","content":"(2, 7) 和 (5, 7)","answer":"待完善","explanation":"解析待完善","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 21:41:24","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":409,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某班级组织了一次环保知识竞赛,共收集了200份有效问卷。统计结果显示,喜欢垃圾分类题目的学生占45%,喜欢节能减排题目的学生占30%,其余学生喜欢资源回收题目。若用扇形统计图表示这些数据,则代表资源回收题目的扇形圆心角的度数是多少?","answer":"B","explanation":"首先计算喜欢资源回收题目的学生所占百分比:100% - 45% - 30% = 25%。扇形统计图中,每个部分的圆心角等于该部分所占百分比乘以360°。因此,资源回收题目对应的圆心角为:25% × 360° = 0.25 × 360° = 90°。故正确答案为B。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 17:27:49","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"75°","is_correct":0},{"id":"B","content":"90°","is_correct":1},{"id":"C","content":"108°","is_correct":0},{"id":"D","content":"120°","is_correct":0}]}]