初中
数学
中等
来源: 教材例题
知识点: 初中数学
答案预览
点击下方'查看答案'按钮查看详细解析并跳转到题目详情页
直接前往详情页
练习完成!
恭喜您完成了本次练习,继续加油提升自己的知识水平!
学习建议
您在一元一次方程的应用方面掌握良好,但仍有提升空间。建议重点复习方程求解步骤和实际应用问题。
[{"id":2196,"subject":"数学","grade":"七年级","stage":"初中","type":"选择题","content":"某学生在数轴上从原点出发,先向右移动5个单位长度,再向左移动8个单位长度。此时该学生所在位置的数是___。","answer":"B","explanation":"从原点(0)出发,向右移动5个单位表示+5,再向左移动8个单位表示-8。计算位置:0 + 5 - 8 = -3。因此,该学生所在位置的数是-3。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-09 14:25:31","updated_at":"2026-01-09 14:25:31","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"3","is_correct":0},{"id":"B","content":"-3","is_correct":1},{"id":"C","content":"13","is_correct":0},{"id":"D","content":"-13","is_correct":0}]},{"id":1969,"subject":"数学","grade":"七年级","stage":"初中","type":"选择题","content":"某学生在研究某次校园义卖活动中不同商品的销售情况时,记录了五种商品的销售额(单位:元):125.6, 98.4, 142.3, 110.8, 135.7。为了分析这组数据的集中趋势,该学生计算了这组数据的中位数和平均数,并发现两者存在一定差异。若将这组数据按从小到大的顺序排列后,位于中间位置的数据与所有数据之和除以数据个数的结果之差最接近以下哪个数值?","answer":"B","explanation":"本题考查数据的收集、整理与描述中中位数与平均数的计算及比较。首先将五种商品的销售额从小到大排序:98.4, 110.8, 125.6, 135.7, 142.3。由于数据个数为5(奇数),中位数是第3个数,即125.6。接着计算平均数:(125.6 + 98.4 + 142.3 + 110.8 + 135.7) ÷ 5 = 612.8 ÷ 5 = 122.56。然后计算中位数与平均数之差:125.6 - 122.56 = 3.04。该值最接近选项B(2.8)。因此,正确答案为B。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"中等","points":1,"is_active":1,"created_at":"2026-01-07 14:48:51","updated_at":"2026-01-07 14:48:51","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"1.2","is_correct":0},{"id":"B","content":"2.8","is_correct":1},{"id":"C","content":"3.6","is_correct":0},{"id":"D","content":"4.4","is_correct":0}]},{"id":613,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某学生在整理班级同学的课外阅读情况时,随机抽取了30名学生进行调查,记录了他们每周课外阅读的时间(单位:小时),并将数据整理如下:5, 6, 7, 8, 5, 6, 9, 7, 8, 6, 5, 7, 8, 9, 6, 7, 5, 8, 7, 6, 9, 8, 7, 6, 5, 7, 8, 9, 6, 7。如果该学生想用一个统计图来直观展示各阅读时间对应的人数,最适合使用的统计图是","answer":"C","explanation":"本题考查的是数据的收集、整理与描述中统计图的选择。题目中给出了30名学生的具体阅读时间数据,属于分类数据(按阅读时间的小时数分类),目的是展示每个阅读时间段对应的人数(频数)。条形统计图适用于展示不同类别数据的频数或数量对比,能够清晰直观地看出各阅读时间的人数分布。折线统计图主要用于显示数据随时间变化的趋势;扇形统计图适合表示各部分占总体的比例;频数分布直方图通常用于连续数据的分组展示,而本题数据为离散的整数小时数,且类别较少,使用条形图更合适。因此,最合适的统计图是条形统计图。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 21:37:54","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"折线统计图","is_correct":0},{"id":"B","content":"扇形统计图","is_correct":0},{"id":"C","content":"条形统计图","is_correct":1},{"id":"D","content":"频数分布直方图","is_correct":0}]},{"id":242,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"某学生计算一个数的相反数时,将原数乘以 -1,得到的结果是 7,那么这个数是____。","answer":"-7","explanation":"根据相反数的定义,一个数的相反数等于这个数乘以 -1。题目中说乘以 -1 后得到 7,说明原数 × (-1) = 7。解这个等式可得:原数 = 7 ÷ (-1) = -7。因此,这个数是 -7。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 14:42:00","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":502,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某班级组织了一次环保知识竞赛,参赛学生共收集了120张答题卡。老师将这些答题卡按正确率分为A、B、C三个等级,其中A级占总数的一半,B级比C级多20张。请问C级答题卡有多少张?","answer":"A","explanation":"设C级答题卡有x张,则B级有(x + 20)张。已知A级占总数的一半,总数为120张,所以A级有120 ÷ 2 = 60张。根据总数量关系列方程:60 + (x + 20) + x = 120。化简得:2x + 80 = 120,解得2x = 40,x = 20。因此C级答题卡有20张,正确答案是A。本题考查一元一次方程的实际应用,结合数据的整理与描述,符合七年级数学知识点。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 18:10:21","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"20张","is_correct":1},{"id":"B","content":"30张","is_correct":0},{"id":"C","content":"40张","is_correct":0},{"id":"D","content":"50张","is_correct":0}]},{"id":2289,"subject":"数学","grade":"七年级","stage":"初中","type":"填空题","content":"在数轴上,点A表示的数是-3,点B与点A的距离为7个单位长度,且点B在原点右侧。若点C位于点A和点B之间,且AC:CB = 2:5,则点C所表示的数为____。","answer":"-1","explanation":"首先,点A表示-3,点B在A右侧且距离为7,因此点B表示的数为-3 + 7 = 4。点C在A和B之间,且AC:CB = 2:5,说明将AB线段分成2+5=7等份,AC占2份。AB总长为7,每份为1单位长度,因此AC = 2。从点A(-3)向右移动2个单位,得到点C的坐标为-3 + 2 = -1。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-09 16:44:29","updated_at":"2026-01-09 16:44:29","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":314,"subject":"数学","grade":"初一","stage":"小学","type":"选择题","content":"某学生在平面直角坐标系中描出点 A(3, 4) 和点 B(-2, 1),他想知道线段 AB 的中点坐标是多少。根据中点坐标公式,正确的结果是:","answer":"A","explanation":"根据平面直角坐标系中两点 A(x₁, y₁) 和 B(x₂, y₂) 的中点坐标公式:中点坐标为 ((x₁ + x₂)\/2, (y₁ + y₂)\/2)。将点 A(3, 4) 和点 B(-2, 1) 代入公式,横坐标为 (3 + (-2))\/2 = 1\/2 = 0.5,纵坐标为 (4 + 1)\/2 = 5\/2 = 2.5。因此,中点坐标为 (0.5, 2.5),对应选项 A。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 15:36:11","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"(0.5, 2.5)","is_correct":1},{"id":"B","content":"(1, 5)","is_correct":0},{"id":"C","content":"(2.5, 0.5)","is_correct":0},{"id":"D","content":"(5, 1)","is_correct":0}]},{"id":2252,"subject":"数学","grade":"七年级","stage":"初中","type":"选择题","content":"数轴上有一点表示的数是-4,若将该点先向右移动7个单位长度,再向左移动2个单位长度,则最终到达的点所表示的数是___。","answer":"C","explanation":"起始点为-4,向右移动7个单位表示加上7,即-4 + 7 = 3;再向左移动2个单位表示减去2,即3 - 2 = 1。因此最终表示的数是1。此题考查数轴上的点与有理数加减运算的实际应用,符合七年级学生对数轴和整数运算的学习要求。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-09 16:03:06","updated_at":"2026-01-09 16:03:06","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"-9","is_correct":0},{"id":"B","content":"-5","is_correct":0},{"id":"C","content":"1","is_correct":1},{"id":"D","content":"9","is_correct":0}]},{"id":1933,"subject":"数学","grade":"七年级","stage":"初中","type":"填空题","content":"在平面直角坐标系中,点A(2, 3)、点B(6, 7),点C在x轴上,且△ABC是以AB为斜边的等腰直角三角形,则点C的横坐标为___。","answer":"4","explanation":"由AB中点M(4,5)为直角顶点对称中心,C在x轴上且满足AC=BC,利用距离公式列方程解得C横坐标为4。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-07 14:10:20","updated_at":"2026-01-07 14:10:20","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":401,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某班级组织了一次环保活动,收集可回收物品。第一周收集了15千克废纸,第二周比第一周多收集了x千克,第三周收集的是前两周总和的一半。已知三周共收集了45千克废纸,求x的值。","answer":"B","explanation":"设第二周收集的废纸为(15 + x)千克,第三周收集的是前两周总和的一半,即(15 + 15 + x) ÷ 2 = (30 + x) ÷ 2 千克。三周总收集量为45千克,因此可列方程:15 + (15 + x) + (30 + x) ÷ 2 = 45。化简方程:30 + x + (30 + x) ÷ 2 = 45。两边同乘以2消去分母:2(30 + x) + (30 + x) = 90,即60 + 2x + 30 + x = 90,合并同类项得90 + 3x = 90,解得3x = 0,x = 10。因此,x的值为10,正确答案是B。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 17:16:35","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"5","is_correct":0},{"id":"B","content":"10","is_correct":1},{"id":"C","content":"15","is_correct":0},{"id":"D","content":"20","is_correct":0}]}]