初中
数学
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10 = 40 元。每本笔记本8元,所以购买的数量为 40 ÷ 8 = 5(本)。因此正确答案是A。本题考查一元一次方程的实际应用,通过简单的减法和除法即可解决,符合七年级学生‘实际问题与一元一次方程’的学习要求。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 11:20:27","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"5本","is_correct":1},{"id":"B","content":"6本","is_correct":0},{"id":"C","content":"4本","is_correct":0},{"id":"D","content":"7本","is_correct":0}]},{"id":10,"subject":"生物","grade":"初一","stage":"初中","type":"选择题","content":"植物细胞和动物细胞都具有的结构是?","answer":"D","explanation":"植物细胞和动物细胞都具有细胞膜、细胞质和细胞核,但植物细胞还具有细胞壁、液泡和叶绿体。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-08-29 16:33:04","updated_at":"2025-11-17 16:31:46","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"细胞壁、细胞膜、细胞质","is_correct":0},{"id":"B","content":"细胞壁、液泡、叶绿体","is_correct":0},{"id":"C","content":"细胞膜、液泡、叶绿体","is_correct":0},{"id":"D","content":"细胞膜、细胞质、细胞核","is_correct":1}]},{"id":313,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某班级为了了解学生最喜欢的课外活动,随机抽取了50名学生进行调查,并将数据整理成如下统计表。已知喜欢阅读的学生人数是喜欢绘画的2倍,且喜欢运动的人数比喜欢绘画的多10人。如果喜欢音乐的学生有8人,那么喜欢绘画的学生有多少人?","answer":"B","explanation":"设喜欢绘画的学生人数为x人。根据题意,喜欢阅读的人数是2x人,喜欢运动的人数是x + 10人,喜欢音乐的有8人。总人数为50人,因此可以列出方程:x(绘画) + 2x(阅读) + (x + 10)(运动) + 8(音乐) = 50。合并同类项得:4x + 18 = 50。解这个一元一次方程:4x = 32,x = 8。所以喜欢绘画的学生有8人。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 15:36:07","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"6人","is_correct":0},{"id":"B","content":"8人","is_correct":1},{"id":"C","content":"10人","is_correct":0},{"id":"D","content":"12人","is_correct":0}]},{"id":1067,"subject":"数学","grade":"七年级","stage":"初中","type":"填空题","content":"在一次班级数学测验中,某学生记录了5名同学的成绩分别为85分、92分、78分、90分和85分。如果去掉一个最高分和一个最低分后,剩余成绩的平均分是____分。","answer":"86.7","explanation":"首先找出5个成绩中的最高分92分和最低分78分,将其去掉后剩下85分、90分和85分。将这三个分数相加:85 + 90 + 85 = 260。然后用总和除以人数3,得到平均分:260 ÷ 3 ≈ 86.7。因此,剩余成绩的平均分是86.7分。本题考查数据的收集、整理与描述中的平均数计算,属于简单难度。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-06 08:52:25","updated_at":"2026-01-06 08:52:25","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":520,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某班级组织了一次环保知识竞赛,共收集了50份有效问卷。统计结果显示,有28人答对了第一题,有25人答对了第二题,有15人两道题都答对了。那么,两道题都没有答对的人数是多少?","answer":"A","explanation":"本题考查数据的收集、整理与描述中的集合思想应用。已知总人数为50人,答对第一题的有28人,答对第二题的有25人,两道题都答对的有15人。根据容斥原理,至少答对一道题的人数为:28 + 25 - 15 = 38人。因此,两道题都没有答对的人数为:50 - 38 = 12人。故正确答案为A。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 18:24:43","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"12","is_correct":1},{"id":"B","content":"13","is_correct":0},{"id":"C","content":"14","is_correct":0},{"id":"D","content":"15","is_correct":0}]},{"id":574,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某学生在整理班级同学的课外阅读时间时,记录了5位同学一周内每天阅读的分钟数,分别为:25、30、35、40、45。如果这5位同学每天阅读时间都增加10分钟,那么他们新的平均阅读时间是多少分钟?","answer":"C","explanation":"首先计算原始数据的平均阅读时间:(25 + 30 + 35 + 40 + 45) ÷ 5 = 175 ÷ 5 = 35(分钟)。每位同学的阅读时间都增加10分钟,相当于整体平均数也增加10分钟。因此新的平均阅读时间为:35 + 10 = 45(分钟)。本题考查数据的整理与描述中的平均数概念,属于简单难度,符合七年级数学课程要求。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 19:55:35","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"35","is_correct":0},{"id":"B","content":"40","is_correct":0},{"id":"C","content":"45","is_correct":1},{"id":"D","content":"50","is_correct":0}]},{"id":532,"subject":"数学","grade":"初一","stage":"小学","type":"选择题","content":"某班级组织学生参加植树活动,共收集了120棵树苗。如果每行种植6棵树苗,可以种多少行?如果每行多种2棵,即每行种8棵,那么可以少种几行?","answer":"A","explanation":"首先计算每行种6棵树苗时,可以种多少行:120 ÷ 6 = 20行。然后计算每行种8棵树苗时,可以种多少行:120 ÷ 8 = 15行。因此,比原来少种了20 - 15 = 5行。所以正确答案是A选项:20行;少种5行。本题考查的是有理数中的除法运算及实际应用,属于简单难度的应用题。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 18:39:50","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"20行;少种5行","is_correct":1},{"id":"B","content":"18行;少种6行","is_correct":0},{"id":"C","content":"20行;少种4行","is_correct":0},{"id":"D","content":"15行;少种3行","is_correct":0}]}]