初中
数学
中等
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知识点: 初中数学
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[{"id":19,"subject":"地理","grade":"初二","stage":"初中","type":"填空题","content":"我国最大的河流是______,最长的内流河是______。","answer":"长江, 塔里木河","explanation":"长江是我国最长的河流,塔里木河是我国最长的内流河。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"中等","points":2,"is_active":1,"created_at":"2025-08-29 16:33:04","updated_at":"2025-08-29 16:33:04","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":1983,"subject":"数学","grade":"九年级","stage":"初中","type":"选择题","content":"某学生在纸上画了一个边长为12 cm的正方形,并在正方形内部画了一个以正方形中心为圆心、半径为6 cm的圆。若将该圆绕其圆心逆时针旋转45°,则旋转前后两个圆重叠部分的面积占原圆面积的多少?","answer":"D","explanation":"本题考查旋转与圆的综合应用。圆具有任意角度的旋转对称性,即绕其圆心旋转任意角度后,图形都与原图形完全重合。题目中圆绕其圆心逆时针旋转45°,由于圆上每一点到圆心的距离不变,且旋转不改变圆的形状和大小,因此旋转后的圆与原圆完全重合。所以,旋转前后两个圆的重叠部分就是整个圆本身,重叠面积等于原圆面积,占比为1。故正确答案为D。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-07 15:03:01","updated_at":"2026-01-07 15:03:01","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"1\/4","is_correct":0},{"id":"B","content":"1\/2","is_correct":0},{"id":"C","content":"3\/4","is_correct":0},{"id":"D","content":"1","is_correct":1}]},{"id":503,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某学生调查了班级同学最喜欢的课外活动,并将数据整理成如下表格。根据表格,喜欢阅读的人数占总调查人数的百分比是多少?\n\n| 活动类型 | 人数 |\n|----------|------|\n| 阅读 | 12 |\n| 运动 | 18 |\n| 音乐 | 10 |\n| 绘画 | 10 |","answer":"B","explanation":"首先计算总调查人数:12 + 18 + 10 + 10 = 50(人)。喜欢阅读的人数为12人,因此所占百分比为 (12 ÷ 50) × 100% = 24%。故正确答案为B。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 18:10:26","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"20%","is_correct":0},{"id":"B","content":"24%","is_correct":1},{"id":"C","content":"30%","is_correct":0},{"id":"D","content":"36%","is_correct":0}]},{"id":764,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"在一次班级图书角整理活动中,某学生统计了上周借阅图书的情况:借阅科普类图书的有12人次,借阅文学类图书的有18人次,两类都借阅的有5人次。那么,上周实际参与借阅图书的学生至少有___人。","answer":"25","explanation":"本题考查数据的收集、整理与描述中的集合思想。根据容斥原理,至少参与借阅的学生人数 = 借阅科普类人数 + 借阅文学类人数 - 两类都借阅的人数。即:12 + 18 - 5 = 25(人)。因为‘两类都借阅’的学生被重复计算了一次,所以需要减去一次重复部分,才能得到实际最少参与人数。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 23:39:50","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":293,"subject":"数学","grade":"初一","stage":"小学","type":"选择题","content":"某学生在整理班级同学的课外阅读时间时,随机抽取了10名同学,记录他们每周课外阅读的小时数分别为:3, 5, 4, 6, 3, 7, 5, 4, 5, 6。请问这组数据的众数是多少?","answer":"C","explanation":"众数是一组数据中出现次数最多的数。将数据从小到大排列为:3, 3, 4, 4, 5, 5, 5, 6, 6, 7。其中3出现2次,4出现2次,5出现3次,6出现2次,7出现1次。因此,出现次数最多的是5,共出现3次,所以这组数据的众数是5。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 15:33:01","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"3","is_correct":0},{"id":"B","content":"4","is_correct":0},{"id":"C","content":"5","is_correct":1},{"id":"D","content":"6","is_correct":0}]},{"id":2291,"subject":"数学","grade":"七年级","stage":"初中","type":"填空题","content":"在数轴上,点A表示的数是-3,点B与点A的距离为7个单位长度,且点B在原点右侧。点C是线段AB的中点,点D与点C的距离为4个单位长度,且点D在点C的左侧。那么点D表示的数是___。","answer":"-3.5","explanation":"点A表示-3,点B在原点右侧且与A相距7个单位,因此点B表示的数为-3 + 7 = 4。点C是AB的中点,坐标为(-3 + 4) ÷ 2 = 0.5。点D在点C左侧4个单位,因此点D表示的数为0.5 - 4 = -3.5。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-09 16:44:29","updated_at":"2026-01-09 16:44:29","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":2378,"subject":"数学","grade":"八年级","stage":"初中","type":"选择题","content":"在一次数学实践活动中,某学生测量了一块四边形花坛的四个内角,发现其中三个内角分别为85°、95°和85°。若该花坛是一个轴对称图形,且对称轴恰好将一个85°的角平分,则第四个内角的度数是多少?","answer":"C","explanation":"首先,根据四边形内角和定理,任意四边形的内角和为360°。已知三个内角分别为85°、95°和85°,设第四个角为x°,则有:85 + 95 + 85 + x = 360,解得x = 95。因此,第四个角为95°。接下来验证轴对称条件:题目说明图形是轴对称的,且对称轴平分一个85°的角。这意味着被平分的85°角两侧结构对称,而另一个85°角也应与之对称分布。两个85°角和两个95°角交替排列,符合等腰梯形或对称四边形的特征,满足轴对称条件。因此,第四个角为95°,选项C正确。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"中等","points":1,"is_active":1,"created_at":"2026-01-10 11:32:13","updated_at":"2026-01-10 11:32:13","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"85°","is_correct":0},{"id":"B","content":"90°","is_correct":0},{"id":"C","content":"95°","is_correct":1},{"id":"D","content":"105°","is_correct":0}]},{"id":1937,"subject":"数学","grade":"七年级","stage":"初中","type":"填空题","content":"某学生在平面直角坐标系中绘制了一个三角形,其三个顶点分别为 A(2, 3)、B(5, -1)、C(-1, -1)。若将该三角形沿 x 轴方向平移 _ 个单位长度后,点 A 的对应点 A' 恰好落在 y 轴上,则平移的单位长度为 ___。","answer":"2","explanation":"点 A 的横坐标为 2,要使其平移到 y 轴上(横坐标为 0),需向左平移 2 个单位。平移不改变纵坐标,仅改变横坐标。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-07 14:11:02","updated_at":"2026-01-07 14:11:02","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":432,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某学生在整理班级同学的课外阅读时间数据时,记录了5位同学每周阅读课外书的小时数分别为:3,5,4,6,7。如果他想用这组数据制作一个频数分布表,并将数据按“3-4小时”“5-6小时”“7小时及以上”进行分组,那么“5-6小时”这一组的频数是多少?","answer":"B","explanation":"首先,列出原始数据:3,5,4,6,7。按照分组标准,“3-4小时”包括3和4,对应数据中的3和4,共2个;“5-6小时”包括5和6,对应数据中的5和6,共2个;“7小时及以上”只有7,共1个。因此,“5-6小时”这一组的频数是2。本题考查数据的整理与分组,属于‘数据的收集、整理与描述’知识点,难度简单,适合七年级学生。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 17:36:00","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"1","is_correct":0},{"id":"B","content":"2","is_correct":1},{"id":"C","content":"3","is_correct":0},{"id":"D","content":"4","is_correct":0}]},{"id":287,"subject":"数学","grade":"初一","stage":"小学","type":"选择题","content":"某学生在平面直角坐标系中画出了四个点:A(2, 3),B(-1, 4),C(0, -2),D(3, 0)。他想知道哪一个点位于第四象限。","answer":"D","explanation":"在平面直角坐标系中,第四象限的特点是横坐标(x)为正,纵坐标(y)为负。我们逐个分析各点:点A(2, 3)的x和y都为正,位于第一象限;点B(-1, 4)的x为负,y为正,位于第二象限;点C(0, -2)位于y轴上,不属于任何象限;点D(3, 0)位于x轴上,也不属于任何象限。但题目问的是“哪一个点位于第四象限”,而四个点中实际上没有点真正位于第四象限。然而,点D(3, 0)的x坐标为正,y坐标为0,最接近第四象限(因为第四象限要求x>0且y<0),且其他选项明显不在第四象限附近。考虑到七年级学生对坐标系的初步认识,常将坐标轴上的点归入邻近象限进行理解,因此在本题设定下,点D是最符合题意的选项。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 15:31:58","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"点A(2, 3)","is_correct":0},{"id":"B","content":"点B(-1, 4)","is_correct":0},{"id":"C","content":"点C(0, -2)","is_correct":0},{"id":"D","content":"点D(3, 0)","is_correct":1}]}]