某学生在数轴上标记了两个有理数点A和B,点A表示的数是-3/4,点B位于点A右侧且与点A的距离为1.25个单位长度。若点B表示的数为x,则下列叙述中正确的是:
💡 提示:点击下方 "查看答案" 查看解析,或 "提交答案" 后自动显示结果
根据多边形内角和公式 (n - 2) × 180°,五边形的边数 n = 5。代入公式得:(5 - 2) × 180° = 3 × 180° = 540°。因此,五边形的内角和是 540 度。
🏆
练习完成!
恭喜您完成了本次练习,继续加油提升!
💡 学习建议:您在一元一次方程的应用方面掌握良好,但仍有提升空间。建议重点复习方程求解步骤和实际应用问题。
[{"id":796,"content":"在一次班级图书角整理活动中,某学生统计了上周同学们借阅的图书数量,发现科技类图书比文学类图书多借出8本,两类图书共借出46本。设文学类图书借出x本,则科技类图书借出___本,根据题意可列方程为___。","type":"填空题","subject":"数学","grade":"初一","stage":"小学","difficulty":"简单","answer":"x + 8;x + (x + 8) = 46","explanation":"题目中明确指出科技类图书比文学类多8本,若文学类借出x本,则科技类为x + 8本。两类图书共借出46本,因此可列出方程:x + (x + 8) = 46。本题考查用字母表示数量关系及建立一元一次方程的能力,属于‘一元一次方程’知识点,符合七年级教学要求。","options":[]},{"id":2206,"content":"某学生记录了连续五天的气温变化情况,以0℃为标准,高于0℃记为正,低于0℃记为负。其中三天的气温分别为:+3℃、-2℃、-5℃。这三天气温中,哪一天的气温最低?","type":"选择题","subject":"数学","grade":"七年级","stage":"初中","difficulty":"简单","answer":"C","explanation":"在正数和负数中,负数的绝对值越大,表示温度越低。比较-2和-5,-5比-2更小,因此-5℃的那天温度最低。正数+3℃高于0℃,显然不是最低。因此正确答案是C。","options":[{"id":"A","content":"+3℃的那天"},{"id":"B","content":"-2℃的那天"},{"id":"C","content":"-5℃的那天"},{"id":"D","content":"无法确定"}]},{"id":2262,"content":"在数轴上,点A表示的数是-3,点B与点A之间的距离为5个单位长度,且点B在原点的右侧。那么点B表示的数是___。","type":"选择题","subject":"数学","grade":"七年级","stage":"初中","difficulty":"简单","answer":"B","explanation":"点A表示的数是-3,点B与点A的距离为5个单位长度。由于在数轴上向右移动数值增大,且点B在原点右侧,说明点B表示的数大于0。从-3向右移动5个单位:-3 + 5 = 2,因此点B表示的数是2。选项B正确。","options":[{"id":"A","content":"-8"},{"id":"B","content":"2"},{"id":"C","content":"8"},{"id":"D","content":"-2"}]},{"id":1983,"content":"某学生在纸上画了一个边长为12 cm的正方形,并在正方形内部画了一个以正方形中心为圆心、半径为6 cm的圆。若将该圆绕其圆心逆时针旋转45°,则旋转前后两个圆重叠部分的面积占原圆面积的多少?","type":"选择题","subject":"数学","grade":"九年级","stage":"初中","difficulty":"简单","answer":"D","explanation":"本题考查旋转与圆的综合应用。圆具有任意角度的旋转对称性,即绕其圆心旋转任意角度后,图形都与原图形完全重合。题目中圆绕其圆心逆时针旋转45°,由于圆上每一点到圆心的距离不变,且旋转不改变圆的形状和大小,因此旋转后的圆与原圆完全重合。所以,旋转前后两个圆的重叠部分就是整个圆本身,重叠面积等于原圆面积,占比为1。故正确答案为D。","options":[{"id":"A","content":"1\/4"},{"id":"B","content":"1\/2"},{"id":"C","content":"3\/4"},{"id":"D","content":"1"}]},{"id":1940,"content":"某学生在平面直角坐标系中绘制了一个四边形ABCD,其中A(0, 0),B(4, 0),C(4, 3),D(0, 5)。若将该四边形绕原点逆时针旋转90°,得到新四边形A'B'C'D',则点C'的坐标为___。","type":"填空题","subject":"数学","grade":"七年级","stage":"初中","difficulty":"困难","answer":"(-3, 4)","explanation":"绕原点逆时针旋转90°,坐标变换公式为(x, y) → (-y, x)。C(4, 3)变换后为(-3, 4)。","options":[]},{"id":489,"content":"17个","type":"选择题","subject":"数学","grade":"初一","stage":"小学","difficulty":"简单","answer":"待完善","explanation":"解析待完善","options":[]},{"id":573,"content":"某学生测量了一个长方形花坛的长和宽,发现长比宽多2米,且周长为20米。若设花坛的宽为x米,则根据题意可列出一元一次方程,求出花坛的面积是多少平方米?","type":"选择题","subject":"数学","grade":"初一","stage":"初中","difficulty":"简单","answer":"D","explanation":"设花坛的宽为x米,则长为(x + 2)米。根据长方形周长公式:周长 = 2 × (长 + 宽),代入已知条件得:2 × (x + x + 2) = 20。化简得:2 × (2x + 2) = 20 → 4x + 4 = 20 → 4x = 16 → x = 4。因此,宽为4米,长为6米。面积为长 × 宽 = 4 × 6 = 24平方米。故正确答案为D。","options":[{"id":"A","content":"12"},{"id":"B","content":"16"},{"id":"C","content":"20"},{"id":"D","content":"24"}]},{"id":137,"content":"某商店购进一批文具,每支笔的进价是2元,售价是3元。如果商店卖出120支笔,那么一共盈利多少元?","type":"解答题","subject":"数学","grade":"初一","stage":"初中","difficulty":"简单","answer":"120元","explanation":"本题考查有理数运算在实际问题中的应用,属于初一数学中‘有理数的加减乘除’与‘简单方程思想’的基础应用。题目通过生活情境引入盈利计算,要求学生理解‘盈利 = 售价 - 进价’这一基本数量关系,并能进行简单的乘法运算。题目难度为简单,符合初一学生刚接触有理数运算和实际问题建模的认知水平。","options":[]},{"id":610,"content":"某学生在整理班级同学的课外阅读时间时,记录了5位同学每周阅读的小时数分别为:3,5,4,6,2。如果老师要求每位同学的阅读时间都增加相同的整数小时,使得新的数据中位数变为5,那么每位同学至少需要增加多少小时?","type":"选择题","subject":"数学","grade":"初一","stage":"初中","difficulty":"简单","answer":"A","explanation":"原始数据为:3,5,4,6,2。先将数据从小到大排序:2,3,4,5,6。当前中位数是中间的数,即4。设每位同学增加x小时(x为正整数),则新数据为:2+x,3+x,4+x,5+x,6+x。排序后仍为:2+x,3+x,4+x,5+x,6+x,中位数是4+x。要求中位数为5,即4 + x = 5,解得x = 1。因此,每位同学至少需要增加1小时。验证:增加1小时后数据为3,4,5,6,7,排序后中位数为5,符合条件。故正确答案为A。","options":[{"id":"A","content":"1"},{"id":"B","content":"2"},{"id":"C","content":"3"},{"id":"D","content":"4"}]},{"id":2229,"content":"某学生记录了连续三天的气温变化:第一天上升了5℃,第二天下降了3℃,第三天又下降了4℃。如果这三天的气温变化用正数和负数表示,则这三天的气温变化总和为____℃。","type":"填空题","subject":"数学","grade":"七年级","stage":"初中","difficulty":"简单","answer":"-2","explanation":"根据正负数的意义,气温上升用正数表示,下降用负数表示。因此,三天的气温变化分别为:+5℃、-3℃、-4℃。将它们相加:5 + (-3) + (-4) = 5 - 3 - 4 = -2。所以总和为-2℃。","options":[]}]