在平面直角坐标系中,点A的坐标为(2,5),点B在x轴上,且线段AB的长度为13。若点B位于原点右侧,则点B的横坐标为____。
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题目给出面积函数 S = x(12 - 2x),可展开为 S = -2x² + 12x。这是一个开口向下的二次函数,其最大值出现在顶点处。顶点横坐标公式为 x = -b/(2a),其中 a = -2,b = 12。代入得 x = -12 / (2 × (-2)) = 3。因此当 x = 3 米时,面积最大。此时平行于墙的一边为 12 - 2×3 = 6 米,面积为 3×6 = 18 平方米。本题考查一次函数与二次函数在实际问题中的应用,结合几何情境,难度适中,符合八年级学生认知水平。
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[{"id":2425,"content":"某学生测量了一个四边形的两条对角线长度分别为6 cm和8 cm,且两条对角线互相垂直。若该四边形的一组对边分别与两条对角线平行,则这个四边形的面积是( )","type":"选择题","subject":"数学","grade":"八年级","stage":"初中","difficulty":"中等","answer":"B","explanation":"根据题意,四边形的两条对角线互相垂直,长度分别为6 cm和8 cm。当四边形的对角线互相垂直时,其面积公式为:面积 = (1\/2) × 对角线₁ × 对角线₂。代入数据得:面积 = (1\/2) × 6 × 8 = 24 cm²。题目中补充条件“一组对边分别与两条对角线平行”,说明该四边形为菱形或更一般的对角线互相垂直的四边形(如筝形),但不影响面积公式的适用性,因为只要对角线互相垂直,面积公式即成立。因此正确答案为B。","options":[{"id":"A","content":"12 cm²"},{"id":"B","content":"24 cm²"},{"id":"C","content":"36 cm²"},{"id":"D","content":"48 cm²"}]},{"id":392,"content":"在一次班级环保活动中,某学生记录了连续5天每天收集的废旧纸张重量(单位:千克),分别为:2.5、3、2.8、3.2、2.7。如果该学生想估算接下来3天总共能收集多少千克废旧纸张,他决定用这5天的平均数来预测。那么,他预测的接下来3天总共能收集的废旧纸张重量最接近以下哪个数值?","type":"选择题","subject":"数学","grade":"初一","stage":"初中","difficulty":"简单","answer":"B","explanation":"首先计算5天收集废旧纸张的平均重量:(2.5 + 3 + 2.8 + 3.2 + 2.7) ÷ 5 = 14.2 ÷ 5 = 2.84(千克\/天)。然后用这个平均数乘以3天,得到预测总量:2.84 × 3 = 8.52(千克)。由于题目要求选择最接近的数值,8.52千克最接近9千克(与8.5千克相比,8.52更接近9),因此正确答案是B。本题考查了数据的收集、整理与描述中的平均数计算及简单应用,符合七年级数学课程内容。","options":[{"id":"A","content":"8.5千克"},{"id":"B","content":"9千克"},{"id":"C","content":"8.7千克"},{"id":"D","content":"9.3千克"}]},{"id":2023,"content":"在一次校园植物测量活动中,一名学生测得一棵树底部到地面的垂直高度为4米,同时测得从树顶到地面某固定标志点的水平距离为3米。若该学生站在标志点处,视线与地面成直角三角形的斜边,则树顶到该标志点的直线距离是多少米?","type":"选择题","subject":"数学","grade":"八年级","stage":"初中","difficulty":"简单","answer":"A","explanation":"根据题意,树高4米为直角三角形的一条直角边,水平距离3米为另一条直角边,所求的直线距离为斜边。应用勾股定理:斜边² = 3² + 4² = 9 + 16 = 25,因此斜边 = √25 = 5(米)。故正确答案为A。","options":[{"id":"A","content":"5"},{"id":"B","content":"6"},{"id":"C","content":"7"},{"id":"D","content":"√7"}]},{"id":2449,"content":"某公园内有一块平行四边形花坛ABCD,测得AB = 8米,AD = 5米,对角线AC = √89米。现要在花坛内修建一条从顶点B到边CD的垂直通道,该通道的长度为___米。","type":"填空题","subject":"数学","grade":"八年级","stage":"初中","difficulty":"中等","answer":"4","explanation":"利用勾股定理验证平行四边形对角线关系,再通过面积法求高:S = AB × h = (1\/2) × AC × BD 的变形不适用,应直接用S = 底×高,结合向量或坐标法可得高为4米。","options":[]},{"id":179,"content":"小明去文具店买笔记本,每本笔记本的价格是8元。他买了5本,付给收银员50元。请问他应该找回多少钱?","type":"选择题","subject":"数学","grade":"初一","stage":"小学","difficulty":"简单","answer":"A","explanation":"首先计算小明购买5本笔记本的总花费:8元\/本 × 5本 = 40元。然后从他付的50元中减去总花费:50元 - 40元 = 10元。因此,收银员应找回10元。正确答案是A。","options":[{"id":"A","content":"10元"},{"id":"B","content":"12元"},{"id":"C","content":"15元"},{"id":"D","content":"18元"}]},{"id":231,"content":"某学生在计算一个数减去 8 时,误将减号看成了加号,结果得到 25。那么正确的计算结果应该是____。","type":"填空题","subject":"数学","grade":"初一","stage":"小学","difficulty":"简单","answer":"9","explanation":"设这个数为 x。根据题意,学生错误地计算了 x + 8 = 25,因此可以求出 x = 25 - 8 = 17。正确的计算应为 17 - 8 = 9。所以正确答案是 9。","options":[]},{"id":1096,"content":"在一次班级大扫除中,某学生负责统计同学们带来的清洁工具数量。他发现扫帚的数量比拖把多5把,且两种工具的总数是27把。如果设拖把的数量为x把,则根据题意可列出一元一次方程:________。","type":"填空题","subject":"数学","grade":"七年级","stage":"初中","difficulty":"简单","answer":"x + (x + 5) = 27","explanation":"题目中设拖把的数量为x把,由于扫帚比拖把多5把,因此扫帚的数量为x + 5把。两种工具的总数为27把,所以拖把数量加上扫帚数量等于27,即 x + (x + 5) = 27。这是一道基于实际问题建立一元一次方程的题目,考查学生将文字信息转化为数学表达式的能力,符合七年级一元一次方程的知识点要求。","options":[]},{"id":2464,"content":"如图,在平面直角坐标系中,点 A(0, 4),点 B(6, 0),点 C 是线段 AB 上的一点,且满足 AC : CB = 1 : 2。点 D 是 x 轴上一点,使得 △ACD 是以 AD 为斜边的等腰直角三角形,∠ACD = 90°。点 E 是线段 CD 的中点。过点 E 作 x 轴的垂线,交直线 AB 于点 F。已知直线 AB 的解析式为 y = -\\\\frac{2}{3}x + 4。\\n\\n(1)求点 C 的坐标;\\n(2)求点 D 的坐标;\\n(3)求 EF 的长度;\\n(4)若将 △ACD 沿直线 CD 翻折,点 A 落在点 A′ 处,求 A′ 的坐标。","type":"解答题","subject":"数学","grade":"八年级","stage":"初中","difficulty":"中等","answer":"待完善","explanation":"解析待完善","options":[]},{"id":1929,"content":"在平面直角坐标系中,点A(2, 3)、点B(5, y)、点C(x, 7)共线,且线段AC的中点在直线y = 2x - 1上,则x + y的值为____。","type":"填空题","subject":"数学","grade":"七年级","stage":"初中","difficulty":"困难","answer":"11","explanation":"利用三点共线斜率相等得(y-3)\/3 = (7-y)\/(x-5),中点((2+x)\/2, 5)代入直线方程得5 = 2·((2+x)\/2) -1,解得x=6,代入得y=5,故x+y=11。","options":[]},{"id":292,"content":"众数是85,中位数是85","type":"选择题","subject":"数学","grade":"初一","stage":"小学","difficulty":"简单","answer":"答案待完善","explanation":"解析待完善","options":[]}]