💡 提示:点击下方 "查看答案" 查看解析,或 "提交答案" 后自动显示结果
根据题意,某学生把'减去5'误看成'加上5',得到结果是20。设这个数为x,则有 x + 5 = 20,解得 x = 15。那么正确的计算应是 15 - 5 = 10。因此正确答案是10。
🏆
练习完成!
恭喜您完成了本次练习,继续加油提升!
💡 学习建议:您在一元一次方程的应用方面掌握良好,但仍有提升空间。建议重点复习方程求解步骤和实际应用问题。
[{"id":2229,"content":"某学生记录了连续三天的气温变化:第一天上升了5℃,第二天下降了3℃,第三天又下降了4℃。如果这三天的气温变化用正数和负数表示,则这三天的气温变化总和为____℃。","type":"填空题","subject":"数学","grade":"七年级","stage":"初中","difficulty":"简单","answer":"-2","explanation":"根据正负数的意义,气温上升用正数表示,下降用负数表示。因此,三天的气温变化分别为:+5℃、-3℃、-4℃。将它们相加:5 + (-3) + (-4) = 5 - 3 - 4 = -2。所以总和为-2℃。","options":[]},{"id":2313,"content":"在一次校园绿化项目中,工人师傅需要在一块矩形空地的对角线上铺设一条石板路。已知这块空地的长为8米,宽为6米。为了估算石板数量,需要先计算对角线的长度。根据勾股定理,这条对角线的长度最接近以下哪个值?","type":"选择题","subject":"数学","grade":"八年级","stage":"初中","difficulty":"简单","answer":"B","explanation":"本题考查勾股定理在矩形对角线计算中的应用。矩形对角线将矩形分成两个直角三角形,其中两条直角边分别为矩形的长和宽。根据勾股定理:对角线² = 长² + 宽² = 8² + 6² = 64 + 36 = 100。因此,对角线 = √100 = 10(米)。故正确答案为B。","options":[{"id":"A","content":"9米"},{"id":"B","content":"10米"},{"id":"C","content":"11米"},{"id":"D","content":"12米"}]},{"id":2318,"content":"某校八年级学生进行体质健康测试,随机抽取了10名学生的1分钟跳绳成绩(单位:次)如下:120, 135, 140, 145, 150, 150, 155, 160, 165, 170。这组数据的中位数和众数分别是多少?","type":"选择题","subject":"数学","grade":"八年级","stage":"初中","difficulty":"简单","answer":"A","explanation":"首先将数据从小到大排列(已排好):120, 135, 140, 145, 150, 150, 155, 160, 165, 170。共有10个数据,为偶数个,因此中位数是第5个和第6个数据的平均数,即(150 + 150) ÷ 2 = 150。众数是出现次数最多的数,150出现了两次,其余数均只出现一次,因此众数为150。故正确答案为A。","options":[{"id":"A","content":"中位数150,众数150"},{"id":"B","content":"中位数147.5,众数150"},{"id":"C","content":"中位数150,众数145"},{"id":"D","content":"中位数147.5,众数145"}]},{"id":136,"content":"一个长方形的长比宽多3厘米,若其周长为26厘米,则这个长方形的宽是____厘米。","type":"填空题","subject":"数学","grade":"初一","stage":"初中","difficulty":"简单","answer":"5","explanation":"设长方形的宽为x厘米,则长为(x + 3)厘米。根据长方形周长公式:周长 = 2 × (长 + 宽),代入得:2 × (x + x + 3) = 26,化简为2 × (2x + 3) = 26,即4x + 6 = 26。解得4x = 20,x = 5。因此,宽为5厘米。本题考查一元一次方程在几何问题中的简单应用,符合初一学生对方程和几何基础的学习要求。","options":[]},{"id":2292,"content":"某学生测量了一块直角三角形纸片的两条直角边,分别为5 cm和12 cm。若要用一根细线沿着纸片的边缘完整绕一圈,所需细线的最短长度是多少?","type":"选择题","subject":"数学","grade":"八年级","stage":"初中","difficulty":"简单","answer":"A","explanation":"题目要求计算直角三角形纸片的周长,即三条边之和。已知两条直角边分别为5 cm和12 cm,首先利用勾股定理求斜边:斜边 = √(5² + 12²) = √(25 + 144) = √169 = 13 cm。因此,周长为 5 + 12 + 13 = 30 cm。所需细线的最短长度即为周长,故正确答案为A。","options":[{"id":"A","content":"30 cm"},{"id":"B","content":"25 cm"},{"id":"C","content":"17 cm"},{"id":"D","content":"13 cm"}]},{"id":293,"content":"某学生在整理班级同学的课外阅读时间时,随机抽取了10名同学,记录他们每周课外阅读的小时数分别为:3, 5, 4, 6, 3, 7, 5, 4, 5, 6。请问这组数据的众数是多少?","type":"选择题","subject":"数学","grade":"初一","stage":"小学","difficulty":"简单","answer":"C","explanation":"众数是一组数据中出现次数最多的数。将数据从小到大排列为:3, 3, 4, 4, 5, 5, 5, 6, 6, 7。其中3出现2次,4出现2次,5出现3次,6出现2次,7出现1次。因此,出现次数最多的是5,共出现3次,所以这组数据的众数是5。","options":[{"id":"A","content":"3"},{"id":"B","content":"4"},{"id":"C","content":"5"},{"id":"D","content":"6"}]},{"id":751,"content":"在一次校园环保活动中,某学生收集了若干千克废纸。若每千克废纸可生产再生纸0.8千克,则该学生收集的废纸共可生产再生纸____千克。已知他最终生产出的再生纸比收集的废纸少6千克,则他最初收集的废纸是____千克。","type":"填空题","subject":"数学","grade":"初一","stage":"小学","difficulty":"简单","answer":"0.8x, 30","explanation":"设该学生收集的废纸为x千克。根据题意,每千克废纸可生产0.8千克再生纸,因此可生产的再生纸为0.8x千克。又知再生纸比废纸少6千克,即x - 0.8x = 6,解得0.2x = 6,x = 30。因此,第一空填0.8x(表示再生纸质量与废纸质量的关系),第二空填30(表示收集的废纸质量)。本题综合考查了一元一次方程的建立与求解,以及有理数的运算,符合七年级数学课程要求。","options":[]},{"id":693,"content":"某学生在整理班级同学的身高数据时,发现最高身高为172厘米,最矮身高为148厘米,则这组数据的极差是___厘米。","type":"填空题","subject":"数学","grade":"初一","stage":"小学","difficulty":"简单","answer":"24","explanation":"极差是一组数据中最大值与最小值的差。题目中最高身高为172厘米,最矮身高为148厘米,因此极差为172 - 148 = 24厘米。本题考查的是数据的收集、整理与描述中的基本概念——极差,属于简单计算,符合七年级数学课程要求。","options":[]},{"id":137,"content":"某商店购进一批文具,每支笔的进价是2元,售价是3元。如果商店卖出120支笔,那么一共盈利多少元?","type":"解答题","subject":"数学","grade":"初一","stage":"初中","difficulty":"简单","answer":"120元","explanation":"本题考查有理数运算在实际问题中的应用,属于初一数学中‘有理数的加减乘除’与‘简单方程思想’的基础应用。题目通过生活情境引入盈利计算,要求学生理解‘盈利 = 售价 - 进价’这一基本数量关系,并能进行简单的乘法运算。题目难度为简单,符合初一学生刚接触有理数运算和实际问题建模的认知水平。","options":[]},{"id":417,"content":"25","type":"选择题","subject":"数学","grade":"初一","stage":"小学","difficulty":"简单","answer":"待完善","explanation":"解析待完善","options":[]}]