某学生在平面直角坐标系中描出三个点 A(2, 3)、B(5, 3) 和 C(5, 6),这三个点构成一个直角三角形。若以 AB 为底边,则该三角形的高对应的长度是 ___。
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该学生误将减法做成了加法,即把原数加上3.5得到了8.2。因此可以先求出原数:8.2 - 3.5 = 4.7。然后用正确的运算方式计算:4.7 - 3.5 = 1.2。所以正确答案是1.2。
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[{"id":798,"content":"在一次班级大扫除中,某学生负责统计同学们带来的清洁工具数量。共收集了12件工具,其中扫帚和拖把的总数是抹布数量的2倍,而抹布比扫帚多1件。设扫帚有x件,拖把有y件,抹布有z件,则可列出二元一次方程组:x + y + z = 12,x + y = 2z,z = x + 1。由这三个方程可得,扫帚有___件。","type":"填空题","subject":"数学","grade":"初一","stage":"初中","difficulty":"简单","answer":"3","explanation":"根据题意,已知三个方程:(1) x + y + z = 12(总工具数),(2) x + y = 2z(扫帚和拖把是抹布的2倍),(3) z = x + 1(抹布比扫帚多1件)。将(3)代入(2)得:x + y = 2(x + 1),化简得 x + y = 2x + 2,即 y = x + 2。再将z = x + 1和y = x + 2代入(1):x + (x + 2) + (x + 1) = 12,合并同类项得 3x + 3 = 12,解得 3x = 9,x = 3。因此,扫帚有3件。","options":[]},{"id":300,"content":"某学生记录了连续5天每天完成数学作业所用的时间(单位:分钟):35,40,30,45,35。这5天完成作业所用时间的众数和中位数分别是多少?","type":"选择题","subject":"数学","grade":"初一","stage":"初中","difficulty":"简单","answer":"A","explanation":"首先将数据从小到大排序:30,35,35,40,45。众数是出现次数最多的数,35出现了两次,其他数各出现一次,因此众数是35。中位数是排序后位于中间位置的数,共有5个数据,中间第3个数是35,因此中位数是35。所以正确答案是A。","options":[{"id":"A","content":"众数是35,中位数是35"},{"id":"B","content":"众数是35,中位数是40"},{"id":"C","content":"众数是40,中位数是35"},{"id":"D","content":"众数是30,中位数是40"}]},{"id":697,"content":"某学生测量了一个长方形花坛的周长和一条边的长度,发现周长是18米,其中一条边长是5米,那么与这条边相邻的另一条边的长度是____米。","type":"填空题","subject":"数学","grade":"初一","stage":"小学","difficulty":"简单","answer":"4","explanation":"长方形的周长公式是:周长 = 2 × (长 + 宽)。已知周长为18米,一条边为5米,设另一条边为x米,则有方程:2 × (5 + x) = 18。两边同时除以2,得5 + x = 9,解得x = 4。因此,另一条边的长度是4米。","options":[]},{"id":2004,"content":"某学生测量了一块直角三角形铁片的边长,其中两条直角边分别为5 cm和12 cm,他需要计算斜边的长度以确定是否适合放入一个边长为13 cm的正方形槽中。请问这块铁片的斜边长度是多少?","type":"选择题","subject":"数学","grade":"八年级","stage":"初中","difficulty":"简单","answer":"B","explanation":"根据勾股定理,在直角三角形中,斜边的平方等于两条直角边的平方和。设斜边为c,则有:c² = 5² + 12² = 25 + 144 = 169。因此,c = √169 = 13(cm)。所以斜边长为13 cm,正好可以放入边长为13 cm的正方形槽中。","options":[{"id":"A","content":"10 cm"},{"id":"B","content":"13 cm"},{"id":"C","content":"15 cm"},{"id":"D","content":"17 cm"}]},{"id":493,"content":"30人","type":"选择题","subject":"数学","grade":"初一","stage":"小学","difficulty":"简单","answer":"待完善","explanation":"解析待完善","options":[]},{"id":152,"content":"下列各数中,属于无理数的是( )","type":"选择题","subject":"数学","grade":"初一","stage":"初中","difficulty":"简单","answer":"C","explanation":"无理数是指不能写成两个整数之比的实数,其小数部分无限不循环。选项A(0.5)可化为1\/2,是有理数;选项B(√4 = 2)是整数,属于有理数;选项D(1\/3)是分数,也是有理数;而选项C(π)是一个著名的无理数,其小数无限不循环,不能表示为分数。因此正确答案是C。","options":[{"id":"A","content":"0.5"},{"id":"B","content":"√4"},{"id":"C","content":"π"},{"id":"D","content":"1\/3"}]},{"id":813,"content":"某学生在整理班级同学最喜爱的运动项目调查数据时,将收集到的原始数据按类别列出后,下一步应该进行的步骤是____。","type":"填空题","subject":"数学","grade":"初一","stage":"小学","difficulty":"简单","answer":"分类整理(或整理成频数分布表)","explanation":"在数据的收集、整理与描述这一知识点中,数据处理的流程通常为:收集数据 → 整理数据 → 描述数据 → 分析数据。当原始数据已经收集完毕后,下一步是将数据进行分类、排序或制成频数分布表,以便更清晰地观察数据的分布情况。因此,空白处应填写“分类整理”或“整理成频数分布表”。","options":[]},{"id":2355,"content":"如图,在平面直角坐标系中,一次函数 y = kx + b 的图像经过点 A(2, 5) 和点 B(−1, −1)。若点 C(m, n) 也在此函数图像上,且满足 m² − 4m + 4 + |n − 5| = 0,则点 C 的坐标为( )。","type":"选择题","subject":"数学","grade":"八年级","stage":"初中","difficulty":"中等","answer":"B","explanation":"首先,利用点 A(2, 5) 和点 B(−1, −1) 求一次函数的解析式。由斜率公式得:k = (5 − (−1)) \/ (2 − (−1)) = 6 \/ 3 = 2。将 k = 2 和点 A(2, 5) 代入 y = kx + b,得 5 = 2×2 + b,解得 b = 1。因此函数解析式为 y = 2x + 1。接着分析条件 m² − 4m + 4 + |n − 5| = 0。注意到 m² − 4m + 4 = (m − 2)²,所以原式可化为 (m − 2)² + |n − 5| = 0。由于平方项和绝对值均为非负数,两者之和为 0 当且仅当每一项都为 0,故有 m − 2 = 0 且 n − 5 = 0,即 m = 2,n = 5。因此点 C 的坐标为 (2, 5),对应选项 B。验证该点是否在函数图像上:当 x = 2 时,y = 2×2 + 1 = 5,符合。故正确答案为 B。","options":[{"id":"A","content":"(0, 1)"},{"id":"B","content":"(2, 5)"},{"id":"C","content":"(4, 9)"},{"id":"D","content":"(1, 3)"}]},{"id":955,"content":"某班级进行了一次数学测验,成绩分布如下:90分以上有8人,80~89分有12人,70~79分有15人,60~69分有10人,60分以下有5人。若将每个分数段的人数用条形统计图表示,则纵轴表示的是____。","type":"填空题","subject":"数学","grade":"初一","stage":"小学","difficulty":"简单","answer":"人数","explanation":"在条形统计图中,横轴通常表示不同的类别(如本题中的分数段),而纵轴表示各类别对应的数量(如人数)。本题中,每个分数段的人数是统计数据,因此纵轴应表示“人数”。这是数据整理与描述中的基本概念,符合七年级数学课程要求。","options":[]},{"id":2266,"content":"在数轴上,点A表示的数是-3,点B表示的数是5。若点C位于点A和点B之间,且AC的长度是CB长度的2倍,那么点C表示的数是多少?","type":"选择题","subject":"数学","grade":"七年级","stage":"初中","difficulty":"中等","answer":"D","explanation":"点A为-3,点B为5,AB之间的距离为5 - (-3) = 8。设CB的长度为x,则AC = 2x,由AC + CB = AB得2x + x = 8,解得x = 8\/3。因此AC = 16\/3。从点A向右移动16\/3个单位,得到点C的坐标为-3 + 16\/3 = (-9 + 16)\/3 = 7\/3。故点C表示的数是7\/3。","options":[{"id":"A","content":"1"},{"id":"B","content":"-1"},{"id":"C","content":"3"},{"id":"D","content":"7\/3"}]}]