初中
数学
中等
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知识点: 初中数学
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[{"id":214,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"一个长方形的长是8厘米,宽是5厘米,它的周长是_厘米。","answer":"26","explanation":"长方形的周长计算公式是:周长 = 2 × (长 + 宽)。将长8厘米和宽5厘米代入公式,得到:2 × (8 + 5) = 2 × 13 = 26。因此,这个长方形的周长是26厘米。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 14:40:05","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":2164,"subject":"数学","grade":"七年级","stage":"初中","type":"选择题","content":"某学生在计算两个有理数的和时,先将两个数的绝对值相加,再根据两数符号确定结果的符号。若他计算的是 -7 与 3 的和,按照他的方法会得到什么结果?实际正确答案又是什么?以下哪一项正确描述了他的错误?","answer":"A","explanation":"该学生错误地将两个有理数的绝对值相加(7 + 3 = 10),然后因两数异号而误判符号为负,得出 -10。但正确方法应为异号相加时用大绝对值减小绝对值(7 - 3 = 4),符号取绝对值较大数的符号(-7 的绝对值大),因此正确答案是 -4。他的错误本质是未掌握异号有理数相加的运算法则,应相减而非相加绝对值。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"中等","points":1,"is_active":1,"created_at":"2026-01-09 13:35:36","updated_at":"2026-01-09 13:35:36","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"他得到的结果是 -10,正确答案是 -4,错误在于没有考虑两数异号时应相减","is_correct":1},{"id":"B","content":"他得到的结果是 10,正确答案是 4,错误在于符号判断错误","is_correct":0},{"id":"C","content":"他得到的结果是 -4,正确答案是 -10,错误在于绝对值相加不正确","is_correct":0},{"id":"D","content":"他得到的结果是 4,正确答案是 -4,错误在于没有取绝对值","is_correct":0}]},{"id":290,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某学生在整理班级同学最喜欢的运动项目调查数据时,制作了如下统计表。已知喜欢篮球的人数比喜欢足球的多6人,且喜欢篮球和足球的总人数为30人。那么喜欢足球的人数是多少?","answer":"B","explanation":"设喜欢足球的人数为x人,则喜欢篮球的人数为(x + 6)人。根据题意,两者总人数为30人,可列出一元一次方程:x + (x + 6) = 30。解这个方程:2x + 6 = 30,2x = 24,x = 12。因此,喜欢足球的人数是12人,对应选项B。本题考查了一元一次方程在数据整理中的简单应用,符合七年级数学课程标准要求。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 15:32:12","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"10人","is_correct":0},{"id":"B","content":"12人","is_correct":1},{"id":"C","content":"18人","is_correct":0},{"id":"D","content":"24人","is_correct":0}]},{"id":234,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"某学生在计算一个数减去3.5时,误将减号看成了加号,结果得到8.2。那么正确的计算结果应该是____。","answer":"1.2","explanation":"该学生误将减法算成加法,即他计算的是:原数 + 3.5 = 8.2。由此可求出原数为:8.2 - 3.5 = 4.7。那么正确的计算应为:4.7 - 3.5 = 1.2。因此正确答案是1.2。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 14:41:11","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":568,"subject":"数学","grade":"初一","stage":"小学","type":"选择题","content":"总人数40人,百分比55%","answer":"待完善","explanation":"解析待完善","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 19:40:39","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":816,"subject":"数学","grade":"初一","stage":"初中","type":"填空题","content":"在一次班级数学测验成绩整理中,老师将分数分为5个等级:A(90分及以上)、B(80-89分)、C(70-79分)、D(60-69分)、E(60分以下)。某学生统计后发现,获得B等级的人数比C等级多4人,而C等级的人数是D等级的2倍。如果D等级有5人,那么B等级有___人。","answer":"14","explanation":"根据题意,D等级有5人,C等级的人数是D等级的2倍,因此C等级有 5 × 2 = 10 人。又因为B等级比C等级多4人,所以B等级有 10 + 4 = 14 人。本题考查的是数据的整理与描述中对数量关系的理解与简单推理,属于七年级数学中‘数据的收集、整理与描述’知识点,难度为简单。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-30 00:36:17","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":296,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某班级在一次数学测验中,随机抽取了10名学生的成绩(单位:分)如下:85,78,92,88,76,90,84,89,87,81。为了了解这组数据的集中趋势,老师要求计算这组数据的中位数。请问这组数据的中位数是多少?","answer":"B","explanation":"要计算中位数,首先需要将数据按从小到大的顺序排列。原始数据为:85,78,92,88,76,90,84,89,87,81。排序后为:76,78,81,84,85,87,88,89,90,92。共有10个数据(偶数个),因此中位数是第5个和第6个数据的平均数。第5个数是85,第6个数是87,所以中位数为 (85 + 87) ÷ 2 = 172 ÷ 2 = 86。因此正确答案是B。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 15:33:32","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"85","is_correct":0},{"id":"B","content":"86","is_correct":1},{"id":"C","content":"87","is_correct":0},{"id":"D","content":"88","is_correct":0}]},{"id":1806,"subject":"数学","grade":"八年级","stage":"初中","type":"选择题","content":"某学生测量了班级10名同学的身高(单位:厘米),数据如下:150,152,153,155,155,156,158,160,162,165。这组数据的中位数和众数分别是多少?","answer":"A","explanation":"首先将数据按从小到大的顺序排列:150,152,153,155,155,156,158,160,162,165。共有10个数据,为偶数个,因此中位数是第5个和第6个数据的平均数,即(155 + 156) ÷ 2 = 155.5。众数是出现次数最多的数,其中155出现了两次,其余数均只出现一次,因此众数是155。所以正确答案是A。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-06 16:17:36","updated_at":"2026-01-06 16:17:36","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"中位数是155.5,众数是155","is_correct":1},{"id":"B","content":"中位数是155,众数是155","is_correct":0},{"id":"C","content":"中位数是156,众数是158","is_correct":0},{"id":"D","content":"中位数是155.5,众数是156","is_correct":0}]},{"id":2435,"subject":"数学","grade":"八年级","stage":"初中","type":"选择题","content":"在一次校园绿化项目中,工人师傅用四块相同的等腰直角三角形地砖拼接成一个轴对称图形,拼接方式如图所示(每块地砖的直角边长为√2米)。若拼接后的大图形是一个正方形,且内部形成一个较小的空白正方形区域,则该空白正方形的面积是多少?","answer":"B","explanation":"每块等腰直角三角形地砖的直角边长为√2米,因此每条直角边对应的斜边(即等腰直角三角形的斜边)长度为:√[(√2)² + (√2)²] = √(2 + 2) = √4 = 2(米)。四块这样的三角形地砖以斜边朝外、直角顶点朝内拼接,可形成一个大正方形,其边长等于原三角形斜边的长度,即2米,故大正方形面积为 2 × 2 = 4 平方米。每块三角形面积为 (1\/2) × √2 × √2 = (1\/2) × 2 = 1 平方米,四块总面积为 4 × 1 = 4 平方米。由于大正方形总面积也为4平方米,说明拼接紧密,但中间空白区域实际由四个直角顶点围成。观察可知,四个直角顶点位于大正方形的中心区域,彼此间距构成一个小正方形,其边长等于两个直角边在水平和垂直方向上的投影差。通过坐标法或几何分析可得,空白正方形边长为√2米,因此面积为 (√2)² = 2 平方米。故正确答案为 B。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"中等","points":1,"is_active":1,"created_at":"2026-01-10 13:07:22","updated_at":"2026-01-10 13:07:22","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"1 平方米","is_correct":0},{"id":"B","content":"2 平方米","is_correct":1},{"id":"C","content":"√2 平方米","is_correct":0},{"id":"D","content":"4 平方米","is_correct":0}]},{"id":799,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"在一次班级大扫除中,某学生负责统计各小组的打扫时间(单位:分钟)。他记录了5个小组的时间分别为:18,22,20,19,21。这些数据的平均数是____。","answer":"20","explanation":"平均数的计算方法是将所有数据相加,再除以数据的个数。计算过程为:(18 + 22 + 20 + 19 + 21) ÷ 5 = 100 ÷ 5 = 20。因此,这组数据的平均数是20。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-30 00:15:32","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]}]