初中
数学
中等
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知识点: 初中数学
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[{"id":296,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某班级在一次数学测验中,随机抽取了10名学生的成绩(单位:分)如下:85,78,92,88,76,90,84,89,87,81。为了了解这组数据的集中趋势,老师要求计算这组数据的中位数。请问这组数据的中位数是多少?","answer":"B","explanation":"要计算中位数,首先需要将数据按从小到大的顺序排列。原始数据为:85,78,92,88,76,90,84,89,87,81。排序后为:76,78,81,84,85,87,88,89,90,92。共有10个数据(偶数个),因此中位数是第5个和第6个数据的平均数。第5个数是85,第6个数是87,所以中位数为 (85 + 87) ÷ 2 = 172 ÷ 2 = 86。因此正确答案是B。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 15:33:32","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"85","is_correct":0},{"id":"B","content":"86","is_correct":1},{"id":"C","content":"87","is_correct":0},{"id":"D","content":"88","is_correct":0}]},{"id":234,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"某学生在计算一个数减去3.5时,误将减号看成了加号,结果得到8.2。那么正确的计算结果应该是____。","answer":"1.2","explanation":"该学生误将减法算成加法,即他计算的是:原数 + 3.5 = 8.2。由此可求出原数为:8.2 - 3.5 = 4.7。那么正确的计算应为:4.7 - 3.5 = 1.2。因此正确答案是1.2。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 14:41:11","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":467,"subject":"数学","grade":"初一","stage":"小学","type":"选择题","content":"42","answer":"待完善","explanation":"解析待完善","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 17:52:39","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":1476,"subject":"数学","grade":"七年级","stage":"初中","type":"解答题","content":"某校七年级组织学生参加环保知识竞赛,竞赛成绩以百分制记录。为分析成绩分布情况,某学生随机抽取了50名参赛学生的成绩,整理后得到如下信息:成绩在60分以下的有5人,60~69分的有8人,70~79分的有12人,80~89分的有15人,90~100分的有10人。已知所有被抽取学生的平均成绩为78.6分,且90~100分这一组中,最低分为92分,最高分为100分,该组平均分为96分。若将80~89分这一组的所有成绩都提高5分,同时将60~69分这一组的所有成绩都降低3分,其余组数据不变,求调整后这50名学生的平均成绩(精确到0.1分)。","answer":"解题步骤如下:\n\n第一步:计算原始总分。\n已知平均成绩为78.6分,总人数为50人,\n所以原始总分 = 78.6 × 50 = 3930(分)。\n\n第二步:计算90~100分组原始总分。\n该组有10人,平均分为96分,\n所以该组原始总分 = 96 × 10 = 960(分)。\n\n第三步:计算其余四组的原始总分。\n其余四组总人数 = 50 - 10 = 40人,\n其余四组原始总分 = 3930 - 960 = 2970(分)。\n\n第四步:分析调整情况。\n- 60~69分组:8人,每人成绩降低3分,总分减少 8 × 3 = 24(分)。\n- 80~89分组:15人,每人成绩提高5分,总分增加 15 × 5 = 75(分)。\n- 其他组(60分以下、70~79分、90~100分)成绩不变,总分不变。\n\n第五步:计算调整后总分。\n调整后总分 = 原始总分 - 24 + 75 = 3930 + 51 = 3981(分)。\n\n第六步:计算调整后平均成绩。\n调整后平均成绩 = 3981 ÷ 50 = 79.62(分)。\n精确到0.1分,结果为79.6分。\n\n答:调整后这50名学生的平均成绩为79.6分。","explanation":"本题综合考查了数据的收集、整理与描述中的频数分布、平均数计算,以及有理数的混合运算和一元一次方程思想的应用(虽未显式列方程,但总分与平均数的关系本质上是线性关系)。解题关键在于理解平均数与总分之间的转换,并能准确计算各组调整对总分的影响。题目设置了真实情境,要求学生在多组数据中识别变化部分,排除干扰信息(如90~100分组的详细数据仅用于验证,实际解题中只需其总分),体现了数据分析能力和逻辑推理能力。难度较高,因涉及多步运算、信息筛选和精确计算,符合困难级别要求。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-06 11:53:43","updated_at":"2026-01-06 11:53:43","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":796,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"在一次班级图书角整理活动中,某学生统计了上周同学们借阅的图书数量,发现科技类图书比文学类图书多借出8本,两类图书共借出46本。设文学类图书借出x本,则科技类图书借出___本,根据题意可列方程为___。","answer":"x + 8;x + (x + 8) = 46","explanation":"题目中明确指出科技类图书比文学类多8本,若文学类借出x本,则科技类为x + 8本。两类图书共借出46本,因此可列出方程:x + (x + 8) = 46。本题考查用字母表示数量关系及建立一元一次方程的能力,属于‘一元一次方程’知识点,符合七年级教学要求。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-30 00:14:51","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":1947,"subject":"数学","grade":"七年级","stage":"初中","type":"填空题","content":"某学生用一根长度为120cm的铁丝围成一个长方形,并将其放置在平面直角坐标系中,使四个顶点坐标均为整数,且长和宽均为正整数。若该长方形对角线长度的平方为680,则其面积为___cm²。","answer":"256","explanation":"设长方形长为x cm,宽为y cm,则2(x+y)=120,得x+y=60;又x²+y²=680。联立解得x=32,y=28或反之,面积为32×28=256。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-07 14:14:02","updated_at":"2026-01-07 14:14:02","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":2460,"subject":"数学","grade":"八年级","stage":"初中","type":"填空题","content":"某学生测量一个等腰三角形的底边为10 cm,腰上的高为8 cm,则该三角形的面积为______cm²。","answer":"40","explanation":"等腰三角形腰上的高将三角形分为两个直角三角形,利用勾股定理可求腰长,但面积直接用底×高÷2计算更简便:10×8÷2=40。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"中等","points":1,"is_active":1,"created_at":"2026-01-10 14:13:00","updated_at":"2026-01-10 14:13:00","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":683,"subject":"数学","grade":"初一","stage":"初中","type":"填空题","content":"在一次班级图书角的统计中,某学生记录了上周同学们借阅科普类书籍和文学类书籍的数量。已知科普类书籍借出15本,文学类书籍借出23本,这两类书籍的平均借阅量为___本。","answer":"19","explanation":"本题考查数据的收集、整理与描述中的平均数计算。平均数 = 总数量 ÷ 总份数。将科普类和文学类书籍的借阅数量相加:15 + 23 = 38(本),再除以类别数2,得到平均借阅量为38 ÷ 2 = 19(本)。因此,空白处应填19。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 22:31:03","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":2768,"subject":"历史","grade":"七年级","stage":"初中","type":"选择题","content":"考古学家在某遗址中发现了大量炭化稻谷、干栏式建筑遗迹和刻画符号的陶器,这些发现最有可能属于哪个新石器时代文化?","answer":"A","explanation":"题干中提到的‘炭化稻谷’表明该地区以水稻种植为主,而水稻主要种植于长江流域;‘干栏式建筑’是适应潮湿环境的典型建筑形式,常见于南方地区;刻画符号的陶器也见于河姆渡遗址。河姆渡文化位于浙江余姚,属于长江流域的新石器时代文化,距今约7000年,符合上述特征。半坡文化位于黄河流域,以粟作农业和半地穴式房屋为特点;大汶口文化和红山文化也主要分布在北方,且不以水稻为主要作物。因此,正确答案为A。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-12 10:40:42","updated_at":"2026-01-12 10:40:42","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"河姆渡文化","is_correct":1},{"id":"B","content":"半坡文化","is_correct":0},{"id":"C","content":"大汶口文化","is_correct":0},{"id":"D","content":"红山文化","is_correct":0}]},{"id":2467,"subject":"数学","grade":"八年级","stage":"初中","type":"解答题","content":"如图,在平面直角坐标系中,点A(0, 4),点B(6, 0),点C在x轴正半轴上,且△ABC是以∠ACB为直角的直角三角形。点D是线段AB上一点,过点D作DE⊥AC于点E,DF⊥BC于点F,使得四边形DECF为矩形。已知矩形DECF的面积S与点D的横坐标x满足关系式:S = -x² + 6x。若点P是该矩形对角线交点,求当点P到原点的距离最小时,点P的坐标。","answer":"待完善","explanation":"解析待完善","solution_steps":"待完善","common_mistakes":"","learning_suggestions":"","difficulty":"中等","points":1,"is_active":1,"created_at":"2026-01-10 14:29:26","updated_at":"2026-01-10 14:29:26","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]}]