初中
数学
中等
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知识点: 初中数学
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[{"id":127,"subject":"数学","grade":"初一","stage":"初中","type":"填空题","content":"一个长方形的长比宽多3厘米,若其周长为26厘米,则这个长方形的宽是______厘米。","answer":"5","explanation":"本题考查初一学生对方程建模和简单一元一次方程求解的理解与应用。题目通过描述长方形长与宽的关系以及周长信息,引导学生设未知数、列方程并求解。虽然涉及几何图形,但核心是代数思维的训练,符合初一上学期学习一元一次方程后的知识水平。题目设计避免了常见的直接计算面积或边长的问题,而是通过‘长比宽多’和‘周长’两个条件建立等量关系,具有一定的综合性和思维层次,但计算简单,属于简单难度。","solution_steps":"Array","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-24 08:54:36","updated_at":"2025-12-24 08:54:36","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":266,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"某学生在解方程 3(x - 4) = 2x + 5 时,第一步将等式两边同时展开,得到 3x - 12 = 2x + 5。接下来,他将含 x 的项移到等式左边,常数项移到右边,得到 ___ = ___。","answer":"3x - 2x = 5 + 12","explanation":"根据解一元一次方程的步骤,移项时要改变项的符号。原式为 3x - 12 = 2x + 5。将 2x 移到左边变为 -2x,将 -12 移到右边变为 +12,因此得到 3x - 2x = 5 + 12。这是移项法则的正确应用,体现了等式两边同时加减同一个整式的变形规则。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"中等","points":1,"is_active":1,"created_at":"2025-12-29 14:57:07","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":1937,"subject":"数学","grade":"七年级","stage":"初中","type":"填空题","content":"某学生在平面直角坐标系中绘制了一个三角形,其三个顶点分别为 A(2, 3)、B(5, -1)、C(-1, -1)。若将该三角形沿 x 轴方向平移 _ 个单位长度后,点 A 的对应点 A' 恰好落在 y 轴上,则平移的单位长度为 ___。","answer":"2","explanation":"点 A 的横坐标为 2,要使其平移到 y 轴上(横坐标为 0),需向左平移 2 个单位。平移不改变纵坐标,仅改变横坐标。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-07 14:11:02","updated_at":"2026-01-07 14:11:02","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":575,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"在一次班级环保活动中,某学生收集了可回收垃圾的重量记录如下:纸类3.5千克,塑料2.8千克,金属1.7千克。如果每千克可回收垃圾可获得0.6元环保积分,那么该学生一共可以获得多少元环保积分?","answer":"A","explanation":"首先计算该学生收集的可回收垃圾总重量:3.5 + 2.8 + 1.7 = 8.0(千克)。然后根据每千克可获得0.6元积分,计算总积分:8.0 × 0.6 = 4.8(元)。因此,该学生一共可以获得4.8元环保积分,正确答案是A。本题考查有理数的加减与乘法运算在实际生活中的应用,符合七年级数学课程中‘有理数’知识点的教学目标。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 19:58:21","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"4.8元","is_correct":1},{"id":"B","content":"5.2元","is_correct":0},{"id":"C","content":"4.2元","is_correct":0},{"id":"D","content":"5.0元","is_correct":0}]},{"id":604,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"在一次班级环保活动中,某学生记录了连续5天每天收集的废旧纸张重量(单位:千克),数据如下:第一天比第二天少2千克,第三天是第一天的2倍,第四天比第三天多1千克,第五天是第二天的1.5倍。已知这五天总共收集了37千克废旧纸张,那么第二天收集了多少千克?","answer":"B","explanation":"设第二天收集的废旧纸张重量为 x 千克。根据题意:\n- 第一天:x - 2 千克\n- 第三天:2(x - 2) = 2x - 4 千克\n- 第四天:(2x - 4) + 1 = 2x - 3 千克\n- 第五天:1.5x 千克\n\n五天总重量为:\n(x - 2) + x + (2x - 4) + (2x - 3) + 1.5x = 37\n合并同类项:\nx - 2 + x + 2x - 4 + 2x - 3 + 1.5x = 37\n(1 + 1 + 2 + 2 + 1.5)x + (-2 -4 -3) = 37\n7.5x - 9 = 37\n7.5x = 46\nx = 6\n\n因此,第二天收集了6千克,正确答案是B。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 21:16:39","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"5千克","is_correct":0},{"id":"B","content":"6千克","is_correct":1},{"id":"C","content":"7千克","is_correct":0},{"id":"D","content":"8千克","is_correct":0}]},{"id":205,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"某学生计算一个数的相反数时,将 -5 写成了 5,那么他计算的是 ___ 的相反数。","answer":"-5","explanation":"相反数的定义是:一个数 a 的相反数是 -a。题目中说某学生将 -5 写成了 5,说明他实际上是把原数的相反数算成了 5。也就是说,-a = 5,那么 a = -5。因此,他计算的是 -5 的相反数。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 14:39:31","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":1865,"subject":"数学","grade":"七年级","stage":"初中","type":"解答题","content":"某城市地铁1号线在平面直角坐标系中沿直线铺设,已知A站坐标为(-3, 2),B站坐标为(5, -6)。现计划在AB之间增设一个临时站点C,使得从A到C的距离与从C到B的距离之比为2:3。同时,为方便乘客换乘,需在C点正东方向4个单位处设置一个公交接驳点D。若一名学生从A站出发,先乘地铁到C站,再步行到D点,求该学生行走的总路程(精确到0.1)。","answer":"1. 设C点坐标为(x, y)。由于C在AB线段上,且AC:CB = 2:3,使用定比分点公式:\n x = (3×(-3) + 2×5)\/(2+3) = (-9 + 10)\/5 = 1\/5 = 0.2\n y = (3×2 + 2×(-6))\/5 = (6 - 12)\/5 = -6\/5 = -1.2\n 所以C点坐标为(0.2, -1.2)\n\n2. D点在C点正东方向4个单位,即横坐标加4,纵坐标不变:\n D点坐标为(0.2 + 4, -1.2) = (4.2, -1.2)\n\n3. 计算AC距离:\n AC = √[(0.2 - (-3))² + (-1.2 - 2)²] = √[(3.2)² + (-3.2)²] = √[10.24 + 10.24] = √20.48 ≈ 4.5\n\n4. 计算CD距离:\n CD = 4(正东方向水平距离)\n\n5. 总路程 = AC + CD ≈ 4.5 + 4 = 8.5\n\n答:该学生行走的总路程约为8.5个单位长度。","explanation":"本题综合考查平面直角坐标系中的定比分点、两点间距离公式及坐标变换。关键步骤是运用定比分点公式确定C点坐标,再根据方向确定D点坐标,最后分段计算距离并求和。难点在于比例关系的坐标化处理和精确计算带小数的平方根。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-07 09:40:17","updated_at":"2026-01-07 09:40:17","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":616,"subject":"数学","grade":"初一","stage":"小学","type":"选择题","content":"(2, 7) 和 (5, 7)","answer":"待完善","explanation":"解析待完善","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 21:41:24","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":2153,"subject":"数学","grade":"七年级","stage":"初中","type":"选择题","content":"某学生在解方程 3(x - 2) = 9 时,第一步写成了 3x - 2 = 9。该学生在哪一步出现了错误?","answer":"B","explanation":"原方程为 3(x - 2) = 9,正确去括号应为 3x - 6 = 9。该学生写成 3x - 2 = 9,说明只将 3 与 x 相乘,而忽略了与 -2 相乘,即未将括号外的数与括号内的每一项相乘,因此错误出现在去括号步骤中的乘法分配律应用不当。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-09 13:00:46","updated_at":"2026-01-09 13:00:46","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"去括号时没有改变括号内的符号","is_correct":0},{"id":"B","content":"去括号时没有将括号外的数与括号内的每一项相乘","is_correct":1},{"id":"C","content":"移项时没有变号","is_correct":0},{"id":"D","content":"合并同类项时计算错误","is_correct":0}]},{"id":2214,"subject":"数学","grade":"七年级","stage":"初中","type":"填空题","content":"某学生在记录一周内每天气温变化时,发现某天的气温比前一天上升了5℃,记作+5℃;第二天又下降了8℃,应记作____℃。","answer":"-8","explanation":"根据正数和负数表示相反意义的量的知识点,气温上升用正数表示,下降则用负数表示。因此,气温下降8℃应记作-8℃。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-09 14:27:19","updated_at":"2026-01-09 14:27:19","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]}]