初中
数学
中等
来源: 教材例题
知识点: 初中数学
答案预览
点击下方'查看答案'按钮查看详细解析并跳转到题目详情页
直接前往详情页
练习完成!
恭喜您完成了本次练习,继续加油提升自己的知识水平!
学习建议
您在一元一次方程的应用方面掌握良好,但仍有提升空间。建议重点复习方程求解步骤和实际应用问题。
[{"id":382,"subject":"数学","grade":"初一","stage":"小学","type":"选择题","content":"某学生在整理班级同学的课外阅读时间时,收集了5名同学每周阅读课外书的平均时间(单位:小时),分别为:3,5,4,6,7。这组数据的中位数是( )","answer":"C","explanation":"要找出这组数据的中位数,首先需要将数据按从小到大的顺序排列:3,4,5,6,7。由于数据个数为5(奇数个),中位数就是正中间的那个数,即第3个数。因此,中位数是5。选项C正确。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 15:55:04","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"4","is_correct":0},{"id":"B","content":"4.5","is_correct":0},{"id":"C","content":"5","is_correct":1},{"id":"D","content":"6","is_correct":0}]},{"id":1967,"subject":"数学","grade":"七年级","stage":"初中","type":"选择题","content":"某学生在整理班级同学最喜欢的课外活动调查结果时,将数据分为四类:阅读、运动、绘画、音乐,并记录了每类的人数分别为:18、24、15、23。为了更直观地展示各类别所占比例,该学生计划绘制扇形统计图。已知扇形统计图中每个扇形的圆心角与其对应类别的人数成正比,且整个圆为360°。请问‘运动’类活动对应的扇形圆心角最接近以下哪个度数?","answer":"B","explanation":"本题考查数据的收集、整理与描述中扇形统计图圆心角的计算方法。首先计算总人数:18 + 24 + 15 + 23 = 80人。‘运动’类有24人,占总人数的比例为24 ÷ 80 = 0.3。扇形圆心角 = 比例 × 360° = 0.3 × 360° = 108°。因此,‘运动’类对应的扇形圆心角为108°,最接近选项B。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"中等","points":1,"is_active":1,"created_at":"2026-01-07 14:48:12","updated_at":"2026-01-07 14:48:12","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"98°","is_correct":0},{"id":"B","content":"108°","is_correct":1},{"id":"C","content":"118°","is_correct":0},{"id":"D","content":"128°","is_correct":0}]},{"id":1082,"subject":"数学","grade":"七年级","stage":"初中","type":"填空题","content":"在一次班级环保活动中,某学生收集了可回收垃圾的重量记录如下:塑料瓶0.8千克,废纸1.2千克,金属罐0.5千克。如果每千克可回收物可获得2元奖励,那么该学生一共可以获得______元奖励。","answer":"5","explanation":"首先计算该学生收集的可回收垃圾总重量:0.8 + 1.2 + 0.5 = 2.5(千克)。然后根据每千克可获得2元奖励,计算总奖励金额:2.5 × 2 = 5(元)。本题考查有理数的加减与乘法在实际问题中的应用,属于简单难度的综合运算题。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-06 08:54:16","updated_at":"2026-01-06 08:54:16","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":276,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"在一次环保知识竞赛中,某班级收集了学生一周内节约用水的数据(单位:升),分别为:12,15,18,15,20,15,14。这组数据的众数和中位数分别是多少?","answer":"A","explanation":"首先,众数是一组数据中出现次数最多的数。数据中15出现了3次,是出现次数最多的,因此众数是15。其次,求中位数需要先将数据按从小到大排列:12,14,15,15,15,18,20。共有7个数据,奇数个,中位数就是正中间的数,即第4个数,也就是15。因此,众数和中位数都是15,正确答案是A。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 15:30:52","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"众数是15,中位数是15","is_correct":1},{"id":"B","content":"众数是15,中位数是14","is_correct":0},{"id":"C","content":"众数是18,中位数是15","is_correct":0},{"id":"D","content":"众数是14,中位数是15","is_correct":0}]},{"id":415,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某学生调查了本班同学最喜欢的课外活动,并将数据整理成如下表格:\n\n| 课外活动 | 人数 |\n|----------|------|\n| 阅读 | 8 |\n| 运动 | 12 |\n| 绘画 | 5 |\n| 音乐 | 7 |\n| 其他 | 3 |\n\n若该班共有35名学生,且所有学生都参与了调查,则喜欢运动的学生所占的百分比最接近以下哪个选项?","answer":"C","explanation":"题目考查的是数据的收集、整理与描述中的百分比计算。喜欢运动的学生有12人,全班共有35人。计算百分比的方法是:(部分 ÷ 总数) × 100%。因此,喜欢运动的学生所占百分比为 (12 ÷ 35) × 100% ≈ 34.29%。这个值最接近34%,所以正确答案是C。题目设计结合真实生活情境,考查学生从表格中提取信息并进行简单计算的能力,符合七年级数学课程要求。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 17:30:41","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"25%","is_correct":0},{"id":"B","content":"30%","is_correct":0},{"id":"C","content":"34%","is_correct":1},{"id":"D","content":"40%","is_correct":0}]},{"id":1766,"subject":"数学","grade":"七年级","stage":"初中","type":"填空题","content":"在平面直角坐标系中,点A的坐标为(2,5),点B在x轴上,且线段AB的长度为13。若点B位于原点右侧,则点B的横坐标为____。","answer":"14","explanation":"根据题意,点A(2, 5),点B在x轴上,设其坐标为(x, 0),且AB = 13。利用两点间距离公式:√[(x - 2)² + (0 - 5)²] = 13。两边平方得:(x - 2)² + 25 = 169,即(x - 2)² = 144。解得x - 2 = ±12,所以x = 14 或 x = -10。由于点B位于原点右侧,x > 0,因此x = 14。故点B的横坐标为14。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-06 15:00:48","updated_at":"2026-01-06 15:00:48","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":675,"subject":"数学","grade":"初一","stage":"初中","type":"填空题","content":"某学生测量了一个矩形花坛的长和宽,发现长比宽多2米。若花坛的周长为20米,则花坛的宽是___米。","answer":"4","explanation":"设花坛的宽为x米,则长为(x + 2)米。根据矩形周长公式:周长 = 2 × (长 + 宽),代入得:2 × (x + x + 2) = 20。化简得:2 × (2x + 2) = 20,即4x + 4 = 20。解这个一元一次方程:4x = 16,x = 4。因此,花坛的宽是4米。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 22:25:10","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":1056,"subject":"数学","grade":"初一","stage":"初中","type":"填空题","content":"某班级进行了一次数学测验,成绩整理如下表所示。已知90分及以上为优秀,则该班本次测验的优秀率为___%。(成绩分布:80分以下有6人,80-89分有10人,90-100分有14人)","answer":"46.7","explanation":"首先计算总人数:6 + 10 + 14 = 30人。优秀人数为90-100分的14人。优秀率 = (优秀人数 ÷ 总人数) × 100% = (14 ÷ 30) × 100% ≈ 46.7%。本题考查数据的收集、整理与描述中的百分比计算,属于简单难度,符合七年级数学课程标准要求。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-30 06:42:48","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":367,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"在平面直角坐标系中,点 A 的坐标是 (3, -2),点 B 的坐标是 (-1, 4)。某学生计算线段 AB 的中点坐标时,使用了公式:中点横坐标为两点横坐标的平均值,中点纵坐标为两点纵坐标的平均值。请问线段 AB 的中点坐标是?","answer":"A","explanation":"根据平面直角坐标系中两点间中点坐标的公式,中点坐标为:横坐标 = (x₁ + x₂) ÷ 2,纵坐标 = (y₁ + y₂) ÷ 2。已知点 A(3, -2),点 B(-1, 4),则中点横坐标为 (3 + (-1)) ÷ 2 = 2 ÷ 2 = 1;中点纵坐标为 (-2 + 4) ÷ 2 = 2 ÷ 2 = 1。因此,中点坐标为 (1, 1)。选项 A 正确。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 15:47:06","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"(1, 1)","is_correct":1},{"id":"B","content":"(2, 2)","is_correct":0},{"id":"C","content":"(1, -3)","is_correct":0},{"id":"D","content":"(-2, 3)","is_correct":0}]},{"id":452,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某班级为了了解学生最喜欢的课外活动,随机抽取了50名学生进行调查,并将结果绘制成扇形统计图。其中,喜欢阅读的学生所占的圆心角为72度。那么,喜欢阅读的学生人数是多少?","answer":"A","explanation":"扇形统计图中,每个部分的圆心角占整个圆(360度)的比例等于该部分人数占总人数的比例。已知喜欢阅读的学生对应的圆心角是72度,总调查人数为50人。计算方法是:(72 ÷ 360) × 50 = 0.2 × 50 = 10。因此,喜欢阅读的学生有10人。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 17:44:55","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"10人","is_correct":1},{"id":"B","content":"12人","is_correct":0},{"id":"C","content":"15人","is_correct":0},{"id":"D","content":"20人","is_correct":0}]}]