初中
数学
中等
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知识点: 初中数学
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[{"id":2149,"subject":"数学","grade":"七年级","stage":"初中","type":"选择题","content":"某学生在解一元一次方程时,将方程 3(x - 2) = 2x + 5 的括号展开后得到 3x - 6 = 2x + 5,接着移项合并同类项。该学生下一步的正确操作是什么?","answer":"B","explanation":"解一元一次方程时,移项要变号。原方程展开后为 3x - 6 = 2x + 5。将 2x 移到左边变为 -2x,将 -6 移到右边变为 +6,因此得到 3x - 2x = 5 + 6。选项B正确体现了移项变号的规则,符合七年级一元一次方程的解法要求。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-09 13:00:46","updated_at":"2026-01-09 13:00:46","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"将 2x 移到左边,-6 移到右边,得到 3x - 2x = 5 - 6","is_correct":0},{"id":"B","content":"将 2x 移到左边,-6 移到右边,得到 3x - 2x = 5 + 6","is_correct":1},{"id":"C","content":"将 3x 移到右边,5 移到左边,得到 -6 - 5 = 2x - 3x","is_correct":0},{"id":"D","content":"两边同时除以 x,得到 3 - 6\/x = 2 + 5\/x","is_correct":0}]},{"id":346,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某学生在整理班级同学的课外阅读时间数据时,记录了10名同学每周阅读的小时数分别为:3,5,4,6,3,7,5,4,5,6。这组数据的众数是多少?","answer":"C","explanation":"众数是指一组数据中出现次数最多的数。将数据从小到大排列为:3,3,4,4,5,5,5,6,6,7。其中,3出现2次,4出现2次,5出现3次,6出现2次,7出现1次。因此,出现次数最多的数是5,所以这组数据的众数是5。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 15:41:14","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"3","is_correct":0},{"id":"B","content":"4","is_correct":0},{"id":"C","content":"5","is_correct":1},{"id":"D","content":"6","is_correct":0}]},{"id":326,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某学生调查了班级同学最喜欢的运动项目,并将数据整理成如下表格。已知喜欢篮球的人数比喜欢足球的多6人,喜欢乒乓球的人数是喜欢羽毛球的2倍,且总人数为40人。如果喜欢足球的有8人,那么喜欢羽毛球的有多少人?","answer":"B","explanation":"根据题意,喜欢足球的有8人,喜欢篮球的比足球多6人,所以喜欢篮球的有 8 + 6 = 14 人。设喜欢羽毛球的有 x 人,则喜欢乒乓球的有 2x 人。总人数为40人,因此可以列出方程:足球人数 + 篮球人数 + 羽毛球人数 + 乒乓球人数 = 总人数,即 8 + 14 + x + 2x = 40。化简得 22 + 3x = 40,解得 3x = 18,x = 6。所以喜欢羽毛球的有6人,正确答案是B。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 15:38:49","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"5人","is_correct":0},{"id":"B","content":"6人","is_correct":1},{"id":"C","content":"7人","is_correct":0},{"id":"D","content":"8人","is_correct":0}]},{"id":2464,"subject":"数学","grade":"八年级","stage":"初中","type":"解答题","content":"如图,在平面直角坐标系中,点 A(0, 4),点 B(6, 0),点 C 是线段 AB 上的一点,且满足 AC : CB = 1 : 2。点 D 是 x 轴上一点,使得 △ACD 是以 AD 为斜边的等腰直角三角形,∠ACD = 90°。点 E 是线段 CD 的中点。过点 E 作 x 轴的垂线,交直线 AB 于点 F。已知直线 AB 的解析式为 y = -\\\\frac{2}{3}x + 4。\\n\\n(1)求点 C 的坐标;\\n(2)求点 D 的坐标;\\n(3)求 EF 的长度;\\n(4)若将 △ACD 沿直线 CD 翻折,点 A 落在点 A′ 处,求 A′ 的坐标。","answer":"待完善","explanation":"解析待完善","solution_steps":"待完善","common_mistakes":"","learning_suggestions":"","difficulty":"中等","points":1,"is_active":1,"created_at":"2026-01-10 14:22:39","updated_at":"2026-01-10 14:22:39","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":2145,"subject":"数学","grade":"七年级","stage":"初中","type":"选择题","content":"某学生在解方程时,将方程 2x + 3 = 7 的解写为 x = 2。以下哪个步骤正确地验证了这个解?","answer":"A","explanation":"验证方程解的正确方法是将解代入原方程,检查等式是否成立。将 x = 2 代入 2x + 3 = 7,得 2×2 + 3 = 4 + 3 = 7,等式成立,说明 x = 2 是正确解。选项 A 正确展示了这一过程。其他选项计算错误或代入方式不正确。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-09 13:00:46","updated_at":"2026-01-09 13:00:46","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"将 x = 2 代入原方程,得到 2×2 + 3 = 7,计算得 4 + 3 = 7,等式成立,因此解正确。","is_correct":1},{"id":"B","content":"将 x = 2 代入原方程,得到 2×2 + 3 = 7,计算得 4 + 3 = 8,等式不成立,因此解错误。","is_correct":0},{"id":"C","content":"将 x = 2 代入原方程,得到 2 + 2 + 3 = 7,计算得 7 = 7,因此解正确。","is_correct":0},{"id":"D","content":"将 x = 2 代入原方程,得到 2×2 = 4,4 + 3 = 6,因此解错误。","is_correct":0}]},{"id":411,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某学生在整理班级同学的课外阅读时间时,记录了5名同学每天阅读的分钟数分别为:20、25、30、35、40。如果他想用条形统计图表示这些数据,每个条形的高度代表对应的阅读时间,那么这5个条形中最高条形与最矮条形的高度差是多少分钟?","answer":"B","explanation":"题目中给出的5个数据是:20、25、30、35、40(单位:分钟)。最高条形对应的是最大值40分钟,最矮条形对应的是最小值20分钟。两者之差为40 - 20 = 20分钟。因此,最高条形与最矮条形的高度差是20分钟。本题考查的是数据的收集、整理与描述中的基本概念,属于简单难度。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 17:28:45","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"15","is_correct":0},{"id":"B","content":"20","is_correct":1},{"id":"C","content":"25","is_correct":0},{"id":"D","content":"30","is_correct":0}]},{"id":187,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"下列各数中,最小的数是( )。","answer":"A","explanation":"本题考查有理数的大小比较。在数轴上,负数位于0的左侧,正数位于0的右侧,因此负数小于0,0小于正数。给出的四个数中,-3是唯一的负数,其余都是非负数(0和正数),所以-3是最小的数。也可以通过比较数值大小直接判断:-3 < 0 < 1 < 2。因此正确答案是A。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 14:01:29","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"-3","is_correct":1},{"id":"B","content":"0","is_correct":0},{"id":"C","content":"1","is_correct":0},{"id":"D","content":"2","is_correct":0}]},{"id":1059,"subject":"数学","grade":"初一","stage":"初中","type":"填空题","content":"在一次环保知识竞赛中,某班级共收集了120份有效问卷。统计结果显示,其中表示‘经常进行垃圾分类’的学生人数是表示‘偶尔进行垃圾分类’人数的2倍少10人。如果设‘偶尔进行垃圾分类’的学生人数为x人,则根据题意可列出一元一次方程:________。","answer":"x + (2x - 10) = 120","explanation":"题目中已知总人数为120人,分为两类:‘偶尔进行垃圾分类’的人数为x人,‘经常进行垃圾分类’的人数比这个数的2倍少10人,即(2x - 10)人。根据总人数等于两部分人数之和,可列出方程:x + (2x - 10) = 120。此方程符合一元一次方程的形式,且基于实际问题建立,考查了学生将文字信息转化为数学表达式的能力。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-30 06:46:46","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":927,"subject":"数学","grade":"初一","stage":"初中","type":"填空题","content":"某学生测量了一个角的度数为75度,这个角的补角是___度。","answer":"105","explanation":"补角是指两个角的和为180度。已知一个角是75度,设其补角为x度,则有方程:75 + x = 180。解这个一元一次方程得:x = 180 - 75 = 105。因此,这个角的补角是105度。本题考查补角的概念及简单的一元一次方程应用,属于几何图形初步与一元一次方程的结合知识点。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-30 02:49:57","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":314,"subject":"数学","grade":"初一","stage":"小学","type":"选择题","content":"某学生在平面直角坐标系中描出点 A(3, 4) 和点 B(-2, 1),他想知道线段 AB 的中点坐标是多少。根据中点坐标公式,正确的结果是:","answer":"A","explanation":"根据平面直角坐标系中两点 A(x₁, y₁) 和 B(x₂, y₂) 的中点坐标公式:中点坐标为 ((x₁ + x₂)\/2, (y₁ + y₂)\/2)。将点 A(3, 4) 和点 B(-2, 1) 代入公式,横坐标为 (3 + (-2))\/2 = 1\/2 = 0.5,纵坐标为 (4 + 1)\/2 = 5\/2 = 2.5。因此,中点坐标为 (0.5, 2.5),对应选项 A。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 15:36:11","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"(0.5, 2.5)","is_correct":1},{"id":"B","content":"(1, 5)","is_correct":0},{"id":"C","content":"(2.5, 0.5)","is_correct":0},{"id":"D","content":"(5, 1)","is_correct":0}]}]