初中
数学
中等
来源: 教材例题
知识点: 初中数学
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2) = 2x + 1 的括号展开后,写成了 3x - 6 = 2x + 1。接下来他正确地移项并合并同类项,最终得到的解是 x = a。请问 a 的值是多少?","answer":"B","explanation":"题目考查一元一次方程的解法,符合初一数学课程内容。从 3x - 6 = 2x + 1 开始,移项得:3x - 2x = 1 + 6,即 x = 7。因此正确答案是 B。题目通过描述解题过程引导学生关注方程变形的逻辑,避免机械记忆,体现思维过程。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-24 11:53:00","updated_at":"2025-12-24 11:53:00","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"5","is_correct":0},{"id":"B","content":"7","is_correct":1},{"id":"C","content":"6","is_correct":0},{"id":"D","content":"8","is_correct":0}]},{"id":575,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"在一次班级环保活动中,某学生收集了可回收垃圾的重量记录如下:纸类3.5千克,塑料2.8千克,金属1.7千克。如果每千克可回收垃圾可获得0.6元环保积分,那么该学生一共可以获得多少元环保积分?","answer":"A","explanation":"首先计算该学生收集的可回收垃圾总重量:3.5 + 2.8 + 1.7 = 8.0(千克)。然后根据每千克可获得0.6元积分,计算总积分:8.0 × 0.6 = 4.8(元)。因此,该学生一共可以获得4.8元环保积分,正确答案是A。本题考查有理数的加减与乘法运算在实际生活中的应用,符合七年级数学课程中‘有理数’知识点的教学目标。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 19:58:21","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"4.8元","is_correct":1},{"id":"B","content":"5.2元","is_correct":0},{"id":"C","content":"4.2元","is_correct":0},{"id":"D","content":"5.0元","is_correct":0}]},{"id":2378,"subject":"数学","grade":"八年级","stage":"初中","type":"选择题","content":"在一次数学实践活动中,某学生测量了一块四边形花坛的四个内角,发现其中三个内角分别为85°、95°和85°。若该花坛是一个轴对称图形,且对称轴恰好将一个85°的角平分,则第四个内角的度数是多少?","answer":"C","explanation":"首先,根据四边形内角和定理,任意四边形的内角和为360°。已知三个内角分别为85°、95°和85°,设第四个角为x°,则有:85 + 95 + 85 + x = 360,解得x = 95。因此,第四个角为95°。接下来验证轴对称条件:题目说明图形是轴对称的,且对称轴平分一个85°的角。这意味着被平分的85°角两侧结构对称,而另一个85°角也应与之对称分布。两个85°角和两个95°角交替排列,符合等腰梯形或对称四边形的特征,满足轴对称条件。因此,第四个角为95°,选项C正确。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"中等","points":1,"is_active":1,"created_at":"2026-01-10 11:32:13","updated_at":"2026-01-10 11:32:13","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"85°","is_correct":0},{"id":"B","content":"90°","is_correct":0},{"id":"C","content":"95°","is_correct":1},{"id":"D","content":"105°","is_correct":0}]},{"id":209,"subject":"数学","grade":"初一","stage":"初中","type":"填空题","content":"某学生计算一个多边形的内角和时,使用了公式 (n - 2) × 180°,其中 n 表示边数。若该多边形有 5 条边,则其内角和为 _ 度。","answer":"540","explanation":"根据多边形内角和公式 (n - 2) × 180°,将边数 n = 5 代入计算:(5 - 2) × 180° = 3 × 180° = 540°。因此,五边形的内角和为 540 度。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 14:39:45","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":655,"subject":"数学","grade":"初一","stage":"初中","type":"填空题","content":"在一次环保主题活动中,某学生记录了连续5天每天节约用水的升数,分别为:3.5升、4.2升、3.8升、4.0升、3.6升。这5天平均每天节约用水______升。","answer":"3.82","explanation":"要计算平均每天节约用水的升数,需将5天的用水量相加后除以天数。计算过程为:(3.5 + 4.2 + 3.8 + 4.0 + 3.6) ÷ 5 = 19.1 ÷ 5 = 3.82(升)。本题考查的是数据的收集、整理与描述中的平均数计算,属于七年级数学中数据处理的基础知识,难度为简单。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 22:13:04","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":608,"subject":"数学","grade":"初一","stage":"小学","type":"选择题","content":"38","answer":"待完善","explanation":"解析待完善","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 21:31:46","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":460,"subject":"数学","grade":"初一","stage":"小学","type":"选择题","content":"144度","answer":"待完善","explanation":"解析待完善","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 17:48:43","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":2464,"subject":"数学","grade":"八年级","stage":"初中","type":"解答题","content":"如图,在平面直角坐标系中,点 A(0, 4),点 B(6, 0),点 C 是线段 AB 上的一点,且满足 AC : CB = 1 : 2。点 D 是 x 轴上一点,使得 △ACD 是以 AD 为斜边的等腰直角三角形,∠ACD = 90°。点 E 是线段 CD 的中点。过点 E 作 x 轴的垂线,交直线 AB 于点 F。已知直线 AB 的解析式为 y = -\\\\frac{2}{3}x + 4。\\n\\n(1)求点 C 的坐标;\\n(2)求点 D 的坐标;\\n(3)求 EF 的长度;\\n(4)若将 △ACD 沿直线 CD 翻折,点 A 落在点 A′ 处,求 A′ 的坐标。","answer":"待完善","explanation":"解析待完善","solution_steps":"待完善","common_mistakes":"","learning_suggestions":"","difficulty":"中等","points":1,"is_active":1,"created_at":"2026-01-10 14:22:39","updated_at":"2026-01-10 14:22:39","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]}]