初中
数学
中等
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知识点: 初中数学
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[{"id":396,"subject":"数学","grade":"初一","stage":"小学","type":"选择题","content":"90度","answer":"答案待完善","explanation":"解析待完善","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 17:15:00","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":2253,"subject":"数学","grade":"七年级","stage":"初中","type":"选择题","content":"在数轴上,点A表示的数是-3,点B与点A之间的距离是5个单位长度,且点B在原点的右侧。那么点B表示的数是多少?","answer":"B","explanation":"点A在数轴上表示-3,点B与点A的距离是5个单位长度。由于点B在原点右侧,说明点B表示的数是正数。从-3向右移动5个单位长度,即-3 + 5 = 2,因此点B表示的数是2。选项B正确。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-09 16:03:06","updated_at":"2026-01-09 16:03:06","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"-8","is_correct":0},{"id":"B","content":"2","is_correct":1},{"id":"C","content":"8","is_correct":0},{"id":"D","content":"-2","is_correct":0}]},{"id":339,"subject":"数学","grade":"初一","stage":"小学","type":"选择题","content":"20","answer":"答案待完善","explanation":"解析待完善","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 15:40:30","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":2225,"subject":"数学","grade":"七年级","stage":"初中","type":"填空题","content":"某学生在记录一周内每天气温变化时,发现某天的气温比前一天上升了3℃,记作+3℃;而另一天的气温比前一天下降了2℃,应记作___℃。","answer":"-2","explanation":"根据正数和负数表示相反意义的量的知识点,气温上升用正数表示,气温下降则应用负数表示。题目中气温下降了2℃,因此应记作-2℃,符合七年级学生对正负数在实际生活中应用的理解要求。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-09 14:27:19","updated_at":"2026-01-09 14:27:19","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":2453,"subject":"数学","grade":"八年级","stage":"初中","type":"填空题","content":"某班级在一次数学测验中,10名学生的成绩分别为:82, 76, 90, 88, 79, 85, 92, 85, 80, 85。这组数据的众数是___,中位数是___。","answer":"85, 84.5","explanation":"众数是出现次数最多的数,85出现3次,最多;将数据从小到大排列后,第5和第6个数为80和89,中位数为(80+89)÷2=84.5。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"中等","points":1,"is_active":1,"created_at":"2026-01-10 13:57:25","updated_at":"2026-01-10 13:57:25","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":723,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"在一次班级图书角整理活动中,某学生统计了上周同学们借阅图书的天数,发现借阅天数最多的为7天,最少的为2天。如果将每位同学的借阅天数都减去3天,则新的数据中,最大值与最小值的差是___天。","answer":"5","explanation":"原数据中最大值为7天,最小值为2天,它们的差是7 - 2 = 5天。当每个数据都减去同一个数(这里是3)时,数据之间的差距(即极差)不会改变。因此,新的最大值是7 - 3 = 4,新的最小值是2 - 3 = -1,它们的差仍然是4 - (-1) = 5天。所以答案是5。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 22:57:40","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":14,"subject":"英语","grade":"初一","stage":"初中","type":"选择题","content":"What is the plural form of \"child\"?","answer":"B","explanation":"\"child\"的复数形式是\"children\"。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-08-29 16:33:04","updated_at":"2025-08-29 16:33:04","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"childs","is_correct":0},{"id":"B","content":"children","is_correct":1},{"id":"C","content":"childes","is_correct":0},{"id":"D","content":"childies","is_correct":0}]},{"id":1317,"subject":"数学","grade":"七年级","stage":"初中","type":"解答题","content":"某校七年级组织学生参加数学实践活动,要求测量并绘制校园内一个不规则多边形花坛的平面图。已知该花坛的边界由五条线段首尾相连组成,形成一个凸五边形。测量小组在平面直角坐标系中确定了五个顶点的坐标分别为 A(2, 3)、B(5, 7)、C(9, 6)、D(8, 2)、E(4, 1)。为了计算花坛的面积,一名学生采用‘分割法’,将五边形 ABCDE 分割为一个三角形和一个梯形。他首先连接对角线 AC,将原五边形分为四边形 ABCE 和三角形 ACD,但发现计算复杂。后来他改用另一种方法:利用坐标几何中的‘鞋带公式’(Shoelace Formula)直接计算多边形面积。请根据该学生的方法,使用鞋带公式计算该五边形花坛的面积,并验证结果是否合理。此外,若每平方米种植 4 株花,且预算允许最多种植 120 株,问该花坛是否适合按标准种植?请说明理由。","answer":"解题步骤如下:\n\n第一步:列出五边形顶点坐标,并按顺时针或逆时针顺序排列(此处按 A→B→C→D→E→A 顺序):\nA(2, 3)\nB(5, 7)\nC(9, 6)\nD(8, 2)\nE(4, 1)\n回到 A(2, 3)\n\n第二步:应用鞋带公式计算面积。\n鞋带公式为:\n面积 = 1\/2 |Σ(x_i * y_{i+1}) - Σ(y_i * x_{i+1})|\n\n计算第一组乘积和(x_i * y_{i+1}):\n2×7 = 14\n5×6 = 30\n9×2 = 18\n8×1 = 8\n4×3 = 12\n总和 = 14 + 30 + 18 + 8 + 12 = 82\n\n计算第二组乘积和(y_i * x_{i+1}):\n3×5 = 15\n7×9 = 63\n6×8 = 48\n2×4 = 8\n1×2 = 2\n总和 = 15 + 63 + 48 + 8 + 2 = 136\n\n第三步:代入公式求面积:\n面积 = 1\/2 × |82 - 136| = 1\/2 × |-54| = 1\/2 × 54 = 27\n\n因此,五边形花坛的面积为 27 平方米。\n\n第四步:计算可种植的花株数量。\n每平方米种植 4 株,则总株数 = 27 × 4 = 108 株。\n\n第五步:判断是否适合种植。\n预算允许最多种植 120 株,而实际需要 108 株,108 < 120,因此在预算范围内。\n\n答:该花坛的面积为 27 平方米,最多可种植 108 株花,未超过预算上限,适合按标准种植。","explanation":"本题综合考查了平面直角坐标系、多边形面积计算(鞋带公式)、有理数运算及实际应用能力。鞋带公式是七年级学生在学习坐标系后可以拓展掌握的一种高效计算任意多边形面积的方法,尤其适用于顶点坐标已知的情况。题目通过真实情境引入,要求学生正确排序顶点、准确进行有理数乘法和加减运算,并最终结合不等式思想(108 ≤ 120)做出合理判断。解题关键在于理解公式的结构、避免符号错误,并能将数学结果应用于实际问题决策中,体现了数学建模的核心素养。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-06 10:53:04","updated_at":"2026-01-06 10:53:04","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":352,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某学生在整理班级同学最喜欢的运动项目调查数据时,制作了如下频数分布表。已知喜欢篮球的人数占总人数的40%,总人数为50人,那么喜欢足球的人数是多少?\n\n| 运动项目 | 人数 |\n|----------|------|\n| 篮球 | ? |\n| 足球 | ? |\n| 乒乓球 | 12 |\n| 羽毛球 | 8 |\n\nA. 10\nB. 15\nC. 20\nD. 25","answer":"A","explanation":"首先根据题意,总人数为50人,喜欢篮球的人数占40%,因此喜欢篮球的人数为:50 × 40% = 20人。\n\n已知喜欢乒乓球的人数为12人,喜欢羽毛球的人数为8人,因此这三类运动的总人数为:20(篮球)+ 12(乒乓球)+ 8(羽毛球)= 40人。\n\n总人数为50人,所以喜欢足球的人数为:50 - 40 = 10人。\n\n因此正确答案是A。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 15:42:55","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"10","is_correct":1},{"id":"B","content":"15","is_correct":0},{"id":"C","content":"20","is_correct":0},{"id":"D","content":"25","is_correct":0}]},{"id":1878,"subject":"语文","grade":"七年级","stage":"初中","type":"选择题","content":"某学生在整理班级同学的数学测验成绩时,制作了如下频数分布表:\n\n| 成绩区间(分) | 频数(人) |\n|----------------|-----------|\n| 60 ≤ x < 70 | 4 |\n| 70 ≤ x < 80 | 8 |\n| 80 ≤ x < 90 | 12 |\n| 90 ≤ x ≤ 100 | 6 |\n\n已知全班平均成绩为81分,若将每位学生的成绩都加上5分后重新计算平均分,并绘制新的频数分布直方图,则下列说法正确的是:\n\nA. 新数据的平均数为86分,各组频数保持不变,但组中值整体增加5\nB. 新数据的平均数为86分,各组频数按比例增加,组距变为原来的1.05倍\nC. 新数据的平均数仍为81分,因为数据分布形状未变,仅位置平移\nD. 新数据的平均数为86分,但90 ≤ x ≤ 100这一组的频数会减少,因为部分学生超过100分","answer":"A","explanation":"本题考查数据的收集、整理与描述中对数据变换的理解。当所有原始数据统一加上一个常数(此处为5)时,平均数也会相应增加该常数,因此新平均数为81 + 5 = 86分。频数反映的是落在各区间内的人数,由于每个数据点都加5,原属于某一区间的数据整体平移到更高区间,但人数不变,故各组频数保持不变。例如,原60≤x<70区间变为65≤x<75,依此类推。组中值(如65、75、85、95)也相应增加5。选项B错误,因为频数不按比例变化;C错误,平均数会变;D错误,虽然理论上成绩可能超过100,但题目未说明有上限限制,且即使超过,也只是进入新区间,不会导致原组频数‘减少’,而是重新归类。因此,A最准确描述了数据变换后的统计特征。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-07 09:54:35","updated_at":"2026-01-07 09:54:35","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"新数据的平均数为86分,各组频数保持不变,但组中值整体增加5","is_correct":1},{"id":"B","content":"新数据的平均数为86分,各组频数按比例增加,组距变为原来的1.05倍","is_correct":0},{"id":"C","content":"新数据的平均数仍为81分,因为数据分布形状未变,仅位置平移","is_correct":0},{"id":"D","content":"新数据的平均数为86分,但90 ≤ x ≤ 100这一组的频数会减少,因为部分学生超过100分","is_correct":0}]}]