初中
数学
中等
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知识点: 初中数学
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(-2))² + (-1 - 3)²] = √[(6)² + (-4)²] = √[36 + 16] = √52 = 2√13\n\nBC = √[(1 - 4)² + (5 - (-1))²] = √[(-3)² + (6)²] = √[9 + 36] = √45 = 3√5\n\nAC = √[(1 - (-2))² + (5 - 3)²] = √[(3)² + (2)²] = √[9 + 4] = √13\n\n周长 = AB + BC + AC = 2√13 + 3√5 + √13 = 3√13 + 3√5\n\n(2) 旋转后顶点坐标:\n\n根据旋转规律 P(x, y) → P'(-y, x):\n\nA(-2, 3) → A'(-3, -2)\nB(4, -1) → B'(1, 4)\nC(1, 5) → C'(-5, 1)\n\n所以 A'(-3, -2),B'(1, 4),C'(-5, 1)\n\n(3) 计算旋转后三角形A'B'C'的面积:\n\n使用坐标法(行列式法)求面积:\n\n面积 = 1\/2 |x₁(y₂ - y₃) + x₂(y₃ - y₁) + x₃(y₁ - y₂)|\n\n代入 A'(-3, -2),B'(1, 4),C'(-5, 1):\n\n= 1\/2 | (-3)(4 - 1) + 1(1 - (-2)) + (-5)((-2) - 4) |\n= 1\/2 | (-3)(3) + 1(3) + (-5)(-6) |\n= 1\/2 | -9 + 3 + 30 |\n= 1\/2 |24| = 12\n\n所以旋转后三角形A'B'C'的面积为12。","explanation":"本题综合考查了平面直角坐标系、两点间距离公式、图形旋转变换以及三角形面积计算等多个知识点。第(1)问要求学生熟练掌握两点间距离公式,并能正确化简含根号的表达式;第(2)问考查图形旋转变换的坐标规律应用,需要理解并记忆逆时针旋转90°的坐标变换规则;第(3)问使用坐标法计算三角形面积,这是七年级拓展内容,要求学生掌握行列式形式的面积公式并能准确代入计算。整个题目将代数运算与几何变换有机结合,思维链条较长,计算量适中但需细致,属于综合性强、思维层次高的困难题。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-06 11:28:50","updated_at":"2026-01-06 11:28:50","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":2455,"subject":"数学","grade":"八年级","stage":"初中","type":"填空题","content":"在一次班级数学测验中,某学生记录了5名同学的数学成绩分别为85分、90分、78分、92分和_分,已知这5个成绩的平均数是86分,则第五个成绩是___分。","answer":"85","explanation":"设第五个成绩为x,根据平均数公式:(85+90+78+92+x)÷5=86,解得x=85。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"中等","points":1,"is_active":1,"created_at":"2026-01-10 14:00:17","updated_at":"2026-01-10 14:00:17","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":2235,"subject":"数学","grade":"七年级","stage":"初中","type":"填空题","content":"某学生在数轴上从原点出发,先向右移动5个单位长度,再向左移动8个单位长度,接着向右移动3个单位长度,最后向左移动4个单位长度。此时该学生所在位置的数与其相反数之和为___。","answer":"0","explanation":"首先计算该学生在数轴上的最终位置:从原点0开始,向右移动5个单位到达+5,再向左移动8个单位到达-3,接着向右移动3个单位到达0,最后向左移动4个单位到达-4。因此,最终位置表示的数是-4。一个数与其相反数之和恒为0,即-4 + 4 = 0。本题综合考查了数轴上的正负数移动、有理数加减运算以及相反数的性质,符合七年级正负数章节的拓展要求,难度较高。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-09 14:39:22","updated_at":"2026-01-09 14:39:22","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":1880,"subject":"语文","grade":"七年级","stage":"初中","type":"选择题","content":"某学生在整理班级数学测验成绩时,制作了如下频数分布表。已知成绩为整数,最低分为40分,最高分为98分,共分为6个分数段,每个分数段的组距相等。若第3个分数段的频数为12,占总人数的24%,且第5个分数段的频数是第1个分数段的3倍,而第2个与第4个分数段的频数之和为20。请问该班级参加测验的学生总人数是多少?","answer":"B","explanation":"本题考查数据的收集、整理与描述中的频数分布与百分比计算,结合一元一次方程求解实际问题。首先,由第3个分数段频数为12,占总人数的24%,可设总人数为x,则有方程:12 = 0.24x,解得x = 50。验证其他条件:总人数为50,则第3段占12人合理。设第1段频数为a,则第5段为3a;第2段与第4段频数和为20。总频数为:a + 第2段 + 12 + 第4段 + 3a + 第6段 = 50。即4a + 20 + 第6段 = 38 → 4a + 第6段 = 18。由于频数为非负整数,a最小为1,最大为4(若a=5,则4a=20>18)。尝试a=3,则4a=12,第6段=6,合理;此时第1段3人,第5段9人,第2+第4=20,第3段12人,第6段6人,总和3+?+12+?+9+6=50,中间两段共20,符合。因此总人数为50,选项B正确。题目融合频数、百分比、方程思想,逻辑严密,难度较高。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-07 09:55:02","updated_at":"2026-01-07 09:55:02","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"40","is_correct":0},{"id":"B","content":"50","is_correct":1},{"id":"C","content":"60","is_correct":0},{"id":"D","content":"70","is_correct":0}]},{"id":1933,"subject":"数学","grade":"七年级","stage":"初中","type":"填空题","content":"在平面直角坐标系中,点A(2, 3)、点B(6, 7),点C在x轴上,且△ABC是以AB为斜边的等腰直角三角形,则点C的横坐标为___。","answer":"4","explanation":"由AB中点M(4,5)为直角顶点对称中心,C在x轴上且满足AC=BC,利用距离公式列方程解得C横坐标为4。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-07 14:10:20","updated_at":"2026-01-07 14:10:20","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]}]