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[{"id":2136,"subject":"数学","grade":"七年级","stage":"初中","type":"选择题","content":"某学生在解一元一次方程时,将方程 2(x - 3) = 4 去括号后得到 2x - 6 = 4,然后他\/她接下来应该进行的正确步骤是:","answer":"D","explanation":"方程 2x - 6 = 4 中,-6 是常数项,为了将含 x 的项单独留在左边,应使用等式的基本性质:两边同时加上6,得到 2x = 10。这是解一元一次方程的标准步骤,符合七年级学生对方程解法的学习要求。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-09 13:00:46","updated_at":"2026-01-09 13:00:46","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"两边同时加上6","is_correct":0},{"id":"B","content":"两边同时除以2","is_correct":0},{"id":"C","content":"两边同时减去6","is_correct":0},{"id":"D","content":"两边同时加上6","is_correct":1}]},{"id":639,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某学生在整理班级同学的课外阅读情况时,绘制了如下条形统计图(描述如下):横轴表示书籍类型(小说、科普、历史、漫画),纵轴表示人数,单位长度为2人。其中小说对应条形高度占3个单位长度,科普占2个单位长度,历史占4个单位长度,漫画占1个单位长度。请问喜欢阅读历史类书籍的学生比喜欢阅读漫画类书籍的学生多多少人?","answer":"C","explanation":"根据题目描述,纵轴单位长度为2人。历史类条形高度为4个单位长度,因此人数为 4 × 2 = 8 人;漫画类条形高度为1个单位长度,因此人数为 1 × 2 = 2 人。喜欢历史类比漫画类多的人数为 8 - 2 = 6 人。因此正确答案是C。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 22:06:38","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"2人","is_correct":0},{"id":"B","content":"4人","is_correct":0},{"id":"C","content":"6人","is_correct":1},{"id":"D","content":"8人","is_correct":0}]},{"id":1018,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"某学生测量了学校花坛一周的温度变化,记录如下:早晨为-2℃,中午上升了7℃,傍晚又下降了3℃。那么傍晚的温度是___℃。","answer":"2","explanation":"早晨温度为-2℃,中午上升7℃,即 -2 + 7 = 5℃;傍晚又下降3℃,即 5 - 3 = 2℃。因此傍晚的温度是2℃。本题考查有理数的加减运算,结合生活情境,符合七年级学生对有理数应用的理解水平。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-30 05:35:37","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":440,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某学生在整理班级同学的课外阅读时间数据时,发现一周内每天阅读时间(单位:分钟)分别为:20,25,30,35,40,45,50。如果将这组数据按从小到大的顺序排列后,位于正中间的那个数称为中位数。那么这组数据的中位数是多少?","answer":"B","explanation":"题目给出了一组7个数据:20,25,30,35,40,45,50。由于数据个数是奇数(7个),中位数就是排序后位于正中间的那个数,即第(7+1)\/2 = 4个数。将数据从小到大排列后,第4个数是35。因此,这组数据的中位数是35。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 17:41:12","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"30","is_correct":0},{"id":"B","content":"35","is_correct":1},{"id":"C","content":"40","is_correct":0},{"id":"D","content":"45","is_correct":0}]},{"id":340,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某班级进行了一次数学测验,成绩分布如下表所示。已知全班共有40名学生,其中成绩在80分及以上的学生人数是60分以下学生人数的3倍,且60分至79分的学生有12人。那么,成绩在80分及以上的学生有多少人?","answer":"B","explanation":"设60分以下的学生人数为x人,则80分及以上的学生人数为3x人。根据题意,全班总人数为40人,60分至79分的学生有12人,因此可以列出方程:x + 12 + 3x = 40。合并同类项得:4x + 12 = 40。两边同时减去12,得4x = 28。两边同时除以4,得x = 7。所以80分及以上的学生人数为3x = 3 × 7 = 21人。因此正确答案是B。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 15:40:35","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"18人","is_correct":0},{"id":"B","content":"21人","is_correct":1},{"id":"C","content":"24人","is_correct":0},{"id":"D","content":"27人","is_correct":0}]},{"id":2168,"subject":"数学","grade":"七年级","stage":"初中","type":"选择题","content":"某学生在数轴上标出三个有理数 a、b、c,已知 a < b < c,且 |a| = |c|,b 是 a 与 c 的算术平均数。若 a + c = -8,则下列说法正确的是:","answer":"B","explanation":"由已知 a + c = -8,且 b 是 a 与 c 的算术平均数,得 b = (a + c) \/ 2 = -8 \/ 2 = -4,因此选项 B 正确。又因为 |a| = |c|,说明 a 和 c 到原点的距离相等,但 a + c = -8 ≠ 0,所以 a 和 c 不互为相反数(相反数之和为 0),排除 A。由于 |a| = |c|,C 错误。a 与 c 不相等(因 a < b < c),距离不可能为 0,D 错误。本题综合考查有理数在数轴上的表示、绝对值、相反数及平均数概念,需多步推理,符合七年级困难题要求。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-09 13:53:54","updated_at":"2026-01-09 13:53:54","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"a 和 c 互为相反数","is_correct":0},{"id":"B","content":"b 的值为 -4","is_correct":1},{"id":"C","content":"c 的绝对值小于 a 的绝对值","is_correct":0},{"id":"D","content":"a 与 c 之间的距离为 0","is_correct":0}]},{"id":977,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"某学生在整理班级同学的课外阅读时间时,将数据分为5组,每组组距为10分钟,其中一组的数据范围是30分钟到40分钟(不包括40分钟)。若该组中有一个数据为35.5分钟,则这个数据属于第____组。","answer":"4","explanation":"题目中说明数据被分为5组,每组组距为10分钟,且给出的数据范围是30分钟到40分钟(不包括40分钟),即[30, 40)。按照从小到大的顺序分组,第一组为[0,10),第二组为[10,20),第三组为[20,30),第四组为[30,40),第五组为[40,50)。35.5分钟落在[30,40)区间内,因此属于第4组。本题考查的是数据的收集、整理与描述中的分组知识,属于简单难度,符合七年级数学课程内容。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-30 04:18:27","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":2506,"subject":"数学","grade":"九年级","stage":"初中","type":"选择题","content":"如图,一个圆形花坛被两条互相垂直的小路分成四个面积相等的扇形区域,其中一条小路的长度为8米。若要在花坛边缘安装一圈LED灯带,则所需灯带的最短长度为多少米?","answer":"A","explanation":"题目中描述两条互相垂直的小路将圆形花坛分成四个面积相等的扇形,说明这两条小路是圆的两条互相垂直的直径。已知其中一条小路的长度为8米,即圆的直径为8米,因此半径r = 4米。要在花坛边缘安装灯带,即求圆的周长。圆的周长公式为C = 2πr = 2π × 4 = 8π(米)。因此,所需灯带的最短长度为8π米,对应选项A。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-10 15:29:31","updated_at":"2026-01-10 15:29:31","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"8π","is_correct":1},{"id":"B","content":"16π","is_correct":0},{"id":"C","content":"4π","is_correct":0},{"id":"D","content":"32π","is_correct":0}]},{"id":563,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某班级进行了一次数学测验,成绩分布如下表所示。已知成绩在80分及以上的人数占总人数的一半,且60分以下的人数比90分以上的人数多2人。如果全班共有40名学生,那么成绩在60分到79分之间的学生有多少人?","answer":"B","explanation":"设成绩在90分以上的人数为x,则60分以下的人数为x + 2。根据题意,80分及以上的人数占总人数的一半,即40 ÷ 2 = 20人。80分及以上包括80-89分和90分以上两部分,因此80-89分的人数为20 - x。全班总人数为40人,所以各分数段人数之和为:60分以下 + 60-79分 + 80-89分 + 90分以上 = 40。代入得:(x + 2) + y + (20 - x) + x = 40,其中y为60-79分的人数。化简得:x + 2 + y + 20 - x + x = 40 → y + x + 22 = 40 → y = 18 - x。又因为80分及以上共20人,其中90分以上为x人,所以x ≤ 20。同时60分以下为x + 2,必须为非负整数,且总人数合理。尝试代入合理值:若x = 4,则60分以下 = 6人,80-89分 = 16人,90分以上 = 4人,此时60-79分人数y = 40 - (6 + 16 + 4) = 14人。验证:80分及以上 = 16 + 4 = 20人,符合条件;60分以下6人比90分以上4人多2人,也符合。因此答案为14人。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 19:27:01","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"12人","is_correct":0},{"id":"B","content":"14人","is_correct":1},{"id":"C","content":"16人","is_correct":0},{"id":"D","content":"18人","is_correct":0}]},{"id":861,"subject":"数学","grade":"初一","stage":"初中","type":"填空题","content":"某学生在调查班级同学最喜欢的课外活动时,收集了以下数据:阅读、运动、绘画、音乐、编程。他将每种活动的人数整理成频数分布表后发现,喜欢运动的人数是喜欢绘画人数的2倍,喜欢音乐的人数比喜欢绘画的多3人,喜欢编程的人数最少,为4人,而喜欢阅读的人数与喜欢音乐的人数相同。如果总共有35人参与调查,那么喜欢绘画的人数是____人。","answer":"6","explanation":"设喜欢绘画的人数为x人,则喜欢运动的人数为2x人,喜欢音乐的人数为x+3人,喜欢编程的人数为4人,喜欢阅读的人数与音乐相同,也为x+3人。根据总人数为35,列出方程:x + 2x + (x+3) + 4 + (x+3) = 35。化简得:5x + 10 = 35,解得5x = 25,x = 6。因此,喜欢绘画的人数是6人。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-30 01:15:43","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]}]